hw3 - amg2845 hw03 McCord(53580 This print-out should have...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
amg2845 – hw03 – McCord – (53580) 1 This print-out should have 31 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. NOTE: If you see a number with an e in it followed by a signed number, you need to realize that the e means × 10 to the power of what follows. For example.. 3 . 56 e - 07 = 3 . 56 × 10 07 Quest is still being tweaked to properly display scientific notation numbers. Some DO display correctly, while others display via the e notation. 001 10.0 points An equilibrium in which processes occur con- tinuously, with NO NET change, is called 1. static equilibrium. 2. heterogeneous equilibrium. 3. dynamic equilibrium. correct 4. homogeneous equilibrium. Explanation: For a system at dynamic equilibrium, al- though the concentrations of the components do not change, the processes continue to oc- cur in the foward and reverse directions at the same rate. 002 10.0 points Explain why equilibium constants are dimen- sionless. 1. Every concentration or pressure that en- ters into K c or K p is really divided by the cor- responding concentration or pressure of the substance in its standard state. correct 2. They are not really dimensionless but we must treat them as such in order to be able to take ln K in the expression Δ G 0 = - RT ln K . 3. They are dimensionless because the pres- sures or concentrations we put in are all for the substances in their standard states. 4. The statement is not true. Equilibrium constants have units that involve some multi- ple of atmospheres or moles per liter. 5. They are dimensionless because concen- trations and pressures have no units. Explanation: The amount of each component is in terms of activity, which is the measured amount (concentration, pressure) divided by the amount of that component in its standard state in that unit. The units in the numera- tor and denominator are identical and cancel out. 003 10.0 points Consider the reaction 2 HgO(s) 2 Hg( ) + O 2 (g) . What is the form of the equilibrium constant K c for the reaction? 1. K c = [Hg] 2 [O 2 ] 2. K c = [O 2 ] [HgO] 2 3. K c = [O 2 ] correct 4. None of the other answers is correct. 5. K c = [Hg] 2 [O 2 ] [HgO] 2 Explanation: Solids and liquids are not included in the K expression. 004 10.0 points The expression for K c for the reaction at equi- librium is 4 NH 3 (g) + 5 O 2 (g) 4 NO(g) + 6 H 2 O(g) 1. [NH 3 ] 4 [O 2 ] 5 2. [NH 3 ] 4 [O 2 ] 5 [NO] 4 [H 2 O] 6 3. [NO] 4 [H 2 O ] 6
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
amg2845 – hw03 – McCord – (53580) 2 4. [NO] 4 [H 2 O] 6 [NH 3 ] 4 [O 2 ] 5 correct Explanation: The equation must be written with the ap- propriate formula and correctly balanced. K c is the equilibrium constant for species in so- lution and equals the mathematical product of the concentrations of the chemical prod- ucts, divided by the mathematical product of the concentrations of the chemical reactants.
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern