CIVL2611_Tutorial-11-Solutions.pdf - CIVL2611 Introductory...

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CIVL2611 – Introductory Fluid Mechanics CIVL9611 – Introductory Fluid Mechanics Tutorial 11 Solutions Question 1: m/s 5 . 0 2 5 5 m 2 m 5 /s m 5 3 = × = = = = = A Q h w Q v The Froude number is calculated as 1 11 . 0 2 81 . 9 5 . 0 < = × = = gh Fr v Therefore, the flow is subcritical. Question 2: We have /s m 3 2 = q Also gh Fr v = For critical flow, Fr = 1, and m 97 . 0 81 . 9 3 3 1 2 3 1 2 = = = g q h c Alternatively, m 97 . 0 1 81 . 9 3 2 3 2 3 = = = = = c c h h h g q gh h q gh Fr v For h > h c , flow) l Subcritica ( 1 2 3 2 3 = < = c h g q h g q Fr Similarly, for h < h c , flow) cal Supercriti ( 1 2 3 2 3 = > = c h g q h g q Fr 1