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2300_HW042_Spring2006

# 2300_HW042_Spring2006 - ECE 2300 CIRCUIT ANALYSIS...

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ECE 2300 – CIRCUIT ANALYSIS HOMEWORK #4 Part 2 – Spring 2006 Due Date: March 2, 2006 Complete problems from Electric Circuits, 7 th Edition, by Nilsson and Riedel: 4.32, 4.34, 4.41, D13, D14, D15, D16 Notes The term “power developed” (Probs. 4.32 and 4.41) is taken to mean the actual power delivered to the circuit. The power dissipated is taken to mean the actual power consumed by the circuit. Additional Problems: D13. Use the mesh-current method to write a complete set of independent equations that could be used to solve this circuit. Do not attempt to solve the equations. Do not attempt to simplify the circuit. i S1 = 0.3[A] + - v S2 = 12[V] R 1 = 47[ ] R 3 = 56[ ] + v S1 = 25 v Y - R 8 = 20[ ] R 5 = 33[ ] i S2 = 0.2 ι X R 4 = 39[ ] R 2 = 82[ ] + - v S3 = 5[V] R 6 = 22[ ] R 7 = 27[ ] i X v Y + - (PEQWS Module 3 Problem 2) Next slide

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D14. Use the mesh-current method to write a complete set of independent equations that could be used to solve this circuit. Do not attempt to solve the equations. Do not attempt to simplify the circuit.
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2300_HW042_Spring2006 - ECE 2300 CIRCUIT ANALYSIS...

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