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Would you like this assignment Graded?YESorNOMA103 Lab Report 6 - Shapes of CurvesName:Student Number:Spring 20171. [5marks] In L’Hospital’s calculus writings from 1696, he illustrated the use of his rule using:limxaf(x) = limxa(2a3x-x4)1/2-a(a2x)1/3a-(ax3)1/4,wherea >0 is a constant.(a) Definef(x) in Maple:f:=(x)->???(substitute appropriately for???and make use of the * formultiplication)Use the commandsa:=1; limit(f(x),x=a); simplify(%);to evaluate limx1f(x).Enter the result in the chartbelow.Use Maple to complete the chart fora= 2,3,4 and then (by looking for a pattern) state limxaf(x) for anya >0.a1234a >0limxaf(x)169329163649169a

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