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Thermo solutions

# Thermo solutions - Answers to Assigned Homework Spring 2006...

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Answers to Assigned Homework, Spring 2006 1.2 77.11 , 755.7 = = m kg W N 1.4 = F 40,990lbf 1.9 =161.6 ft/s v 1.10 T2 = 3060 C 1.14 2 P = 60.67 psia; 3 T =1059.7 °F 2.1 2 1 pe -pe = 0.196kJ/kg ; × -3 2 1 ke -ke = -1.976 10 kJ /kg; = A e 113.22kJ/kg 2.4 3.99 x 10 9 BTU 2.6 ± IN,yield W = 8.29 ft lbf ; ± IN,frac W = 973.32 ft lbf 2.8 = × 6 OUT,1 2 w 2.52 10 (ft lbf lbm) 2.9 a) P2 = 2511.9 kPa, b) -378 kJ/kg 2.11 61,169 ft-lbf/lbm 3.1 a) 8.52 lbf, b) 0.0161 ft3/lbm, c) 62.1 lbm/ft3 3.2 P=1.5536 MPa, v= 1.156 x 10 -3 m3/kg 3.6 3 v(2.0 MPa, 400°C) = 0.1512 (m /kg) 3.9 ( ) × 6 6 6 10 10 e = - lbm =1.24 10 lbm 0.0162 0.01588 3.15 m = 24.6 kg 3.20 b) T = 160.3 C; c) T=45.8 C, d) m = 1.73 kg, e) -4206 kJ 3.32 T2 = 1200 K, T3 = 2400 K, W = +30 kJ 3.36 b). m = 24.11 lbm ; c). 2 P =82.15 psia 4.3 b) P = 54.74 kPa, c) 9.5 cents 4.4 Q = 3143 kJ 4.7 H T = 53.8 K ; 12,in W = 54.8 kJ 4.9 3 T = 83.2 °F 4.11 2 =1081.8 m/s v

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4.12 x = .27 (27%) 4.14 & water m =1211 kg/s 4.15 1472.2 kW 4.16 0.055 kg/s 4.21 513.2 m/s 4.26 Power = +2916.8 kW 4.27 Power = -9506 kW, net heat transfer rate = -2.96 x 10
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