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Unformatted text preview: #31. These two outcomes are equally likely, and one is just as random as the other, because the probability of seeing any particular exact outcome when you flip a coin 10 times is 1 in 2 10 , or 1/1024, or about 0.000976. #40. There are two possible interpretations of this question. (a) You want the probability that you will win at least once in 36 tries. The probability that you will lose in one try is 51/52, so the probability that you will lose 36 times is 51 / 52 36 = .98077 36 = 0.4971 , so the probability that you will win at least once is 1 – 0.4971 = .5029. (b) You want the probability that you lose 35 times and win exactly on the 36 th try. This probability is 51 / 52 35 × 1 / 52 = 0.5068 × 0.01923 = 0.0097. I think interpretation (a) is what is intended. Note: Answers may be rounded off more than in these solutions....
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This note was uploaded on 03/19/2008 for the course M 302 taught by Professor Irwin during the Spring '08 term at University of Texas at Austin.
 Spring '08
 Irwin
 Probability

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