PHY183-Lecture25 - February 24, 2006 Physics for...

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Unformatted text preview: February 24, 2006 Physics for Scientists&Engineers 1 1 Physics for Scientists & Physics for Scientists & Engineers 1 Engineers 1 Spring Semester 2006 Lecture 25 February 24, 2006 Physics for Scientists&Engineers 1 2 Experiment: Totally Inelastic Collision Experiment: Totally Inelastic Collision February 24, 2006 Physics for Scientists&Engineers 1 2 Experiment: Totally Inelastic Collision Experiment: Totally Inelastic Collision February 24, 2006 Physics for Scientists&Engineers 1 3 Ballistic Pendulum Ballistic Pendulum Question: A bullet ( v =300 m/s, m =0.020 kg) hits a block ( M =4.0 kg) and sticks in it. What is the kinetic energy of block+bullet right after impact? Answer: This is obviously a completely inelastic collision Compare: v f = mv m + M = 0.02 4.02 (300 m/s) = 1.49 m/s K = 1 2 ( m + M ) v f 2 = 1 2 m 2 v 2 m + M = 4.5 J K bullet = 1 2 mv 2 = 900 J February 24, 2006 Physics for Scientists&Engineers 1 4 Ballistic Pendulum (2) Ballistic Pendulum (2) Question: If the block is suspended by strings, how high will this pendulum swing Answer: Height from conversion of kinetic energy to potential energy: ( m + M ) gh = K = 1 2 mv 2 m + M !...
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This note was uploaded on 03/19/2008 for the course PHY 183 taught by Professor Wolf during the Spring '08 term at Michigan State University.

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PHY183-Lecture25 - February 24, 2006 Physics for...

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