# m.i lab 3 - = = 0.0048828 V = 5mV 1.3 Q1. When the gain is...

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Lab #3: Introduction to Digital Data Acquisition Amber Mueller February 19, 2008

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1.1 Q1. The minimum resolvable voltage that can be measured with the A/D at a gain of 1 and sampling frequency of 10 KHz is 0.0048828 V. = = 0.0048828 V Q2. The voltage at which the voltage clips at a gain of 10 is 1V. Q3. This voltage is what we would expect from our settings because Range = V/G=10/10=1 Δ 1.2 Q1. With a gain of 1 and a peak-to-peak of 10mV, the smallest voltage change that the A/D can resolve is 5mV. HWQ. This is what we would expect for a 12 bit A/D with a range of 10V and a gain of unity because
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Unformatted text preview: = = 0.0048828 V = 5mV 1.3 Q1. When the gain is changed to 10, the signal appears to be better resolved. 2.4 Q1. There are fluctuations at a resolution of 8. The graph becomes square at 6. The signal is louder and has even more fluctuations at a resolution of 4. Q2. The lowest resolution setting that doesnt seem to compromise the quality of the signal is 10. Fluctuations begin at 8. 3.4 Q1. As the resolution is decreased, there is an increasing amount of white noise. The voice remains consistent until the resolution is at 2, when the voice becomes indistinguishable from the background noise....
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## This note was uploaded on 03/19/2008 for the course EM 319 taught by Professor Kennethm.liechti during the Spring '08 term at University of Texas at Austin.

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m.i lab 3 - = = 0.0048828 V = 5mV 1.3 Q1. When the gain is...

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