EX_2-7.pdf

# EX_2-7.pdf - Homework 2 1 6|(n3 n Base Case n = 0 6|(03 0...

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Homework 2 1. 6 | (n 3 n ) Base Case: n = 0 æ 6 | (0 3 0) =6 , 6 divides 0 , so P ( n ) is true when n = 0 Induction Hypothesis: Assume that P(k) holds: k 3 - k is divisible by 6 for arbitrary integer k Ø 0 Induction Steps: want to prove: (k+1) 3 - (k-1) is divisible by 6
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