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p1044.pdf - n LUU A[U ”I = 9.93 x 10"9 J KE =...

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Unformatted text preview: n, LUU A [U ”I = 9.93 x 10"9 J KE = hv -— (15 = 9.93 x 10“19 J — 7.05 x 10491: 2.88 x 10”19 J 1—18. When a clean surface of silver is irradiated with light of wavelength 230 nm, the kinetic energy 2 the ejected electrons is found to be 0.805 eV. Calculate the work function and the threshold frequency of silver. From Equation 1.6, hc =h - =———KE (15 v A (6.626 X 10'34 1-3) (2.998 x l08 m-s") _ 230 ><10‘9 m = 8.64 X 10—19] - 1.29 X 1049} = 7.35 X 10—19} -19 —O.805eV(1'602X 10 I) leV From Equation 1.7, =—~———————=1.11x10'5Hz «p 7.35 x WW I: 6.626 x 10441-5 90: 1—19. Some data for the kinetic energy of ejected electrons as a function of the wavelength of the incident radiation for the photoelectron effect for sodium metal are A/nm 100 200 300 400 500 KE/eV 10.1 3.94 1.88 0.842 0.222 Plot these data to obtain a straight line, and calculate h from the slope of the line and the work function Q5 from its intercept with the horizontal axis. ...
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