UW Common Math 308 Section 5.1.pdf - WebAssign...

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Current Score :41 / 41Due :Tuesday, November 14 2017 11:00 PM PST1.2/2 points |Previous AnswersHoltLinAlg2 5.1.004.Findfor the given matrixA.M23=[0, ­5, 0; 0, 5, 0; 4, 2, 2]M31=[­5, 6, 0; 3, ­3, 0; 2, 3, 2]Solution or Explanation2.2/2 points |Previous AnswersHoltLinAlg2 5.1.008.FindC13andC22for the given matrixA.C13=5454C22=1818Solution or ExplanationUW Common Math 308 Section 5.1 (Homework)KEIRA HANSENMath 308, section F, Fall 2017Instructor: Lucas BrauneWebAssignThe due date for this assignment is past.Your work can be viewed below, but no changes can be made.Important!Before you view the answer key, decide whether or not you plan to request an extension. Your Instructor maynotgrant you an extension if youhave viewed the answer key. Automatic extensions are not granted if you have viewed the answer key.Request ExtensionM23andM31A=0560133005304232M23=M31=0500504225603302329205−2−7782C13= (−1)1+3|M13| == (5)(8) − (−2)(7) =54C22= (−1)2+2|M22| == (9)(2) − (0)(7) =185 −278907 2
3.4/4 points |Previous AnswersHoltLinAlg2 5.1.014.Find the determinant for the given matrixAin two ways, by using cofactor expansion along the indicated row or column.(a) along the first rowdet(A) =­8­8(b) along the third columndet(A) =­8­8Use the determinant to decide ifis invertible.SinceAisisinvertible, and henceTisisinvertible.Solution or ExplanationA=9150190139010190T(x) =A(x)det(A)0,det(A) =a11C11+a12C12+a13C13+a14C14
(b) Using the third column,det(A)0,
4.2/2 points |Previous AnswersHoltLinAlg2 5.1.030.Find all real values ofasuch that the given matrix is not invertible. (HINT: Think determinants, not row operations. Enteryour answers as a comma­separated list. If an answer does not exist, enter DNE.)Solution or Explanationhas no solutionsAis invertible for all

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Term
Winter
Professor
Milakis
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