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Unformatted text preview: 10 Gases Visualizing Concepts 10.1 10.4 Over time, the gases will mix perfectly. Each bulb will contain 4 blue and 3 red atoms. The “blue” gas has the greater partial pressure after mixing, because it has the greater number of particles (at the same T and V as the “red” gas.) 10.7 (a) At constant temperature, the “average” (really root mean square) speed of a collection of gas particles is inversely related to molar mass; the lighter the particle, the faster it moves. Therefore, curve B represents He and curve A represents O 2 . Curve B has the higher avg. molecular speed and He is the lighter gas. Curve A has the lower avg. molecular speed and O 2 is the heavier gas. (b) For the same gas “avg” kinetic energy (1/2 mv 2 ), and therefore “avg” speed (v) is directly related to Kelvin temperature. Curve A is the lower temperature and curve B is the higher temperature. Gas Characteristics; Pressure 10.9 In the gas phase molecules are far apart, while in the liquid they are touching. (a) A gas is much less dense than a liquid because most of the volume of a gas is empty space. (b) A gas is much more compressible because of the distance between molecules. (c) Gaseous molecules are so far apart that there is no barrier to mixing, regardless of the identity of the molecule. All mixtures of gases are homogeneous. Liquid molecules are touching. In order to mix, they must displace one another. Similar molecules displace each other and form homogeneous mixtures. Very dissimilar molecules form heterogeneous mixtures. 115 10 Gases Solutions to Red Exercises 10.11 Analyze . Given: mass, area. Find: pressure. Plan . P=F/A = m × a/A; use this relationship, paying attention to units. Solve . . m to area and kg to mass Change s m kg 1 m 1 s m kg 1 m N 1 Pa 1 2 2 2 2 2 • • = × = = 2 6 2 2 2 2 2 s m kg 10 1.8 m 1 in 39.4 lb 1 kg 454 . s 1 m 81 . 9 in 0.50 lb 130 A a m P • × = × × × = × = = 1.8 × 10 6 Pa = 1.8 × 10 3 kPa Check . [1.30 × 10 × 0.5 × (40) 2 /0.5] ≈ (130 × 16,000) ≈ 2.0 × 10 6 Pa ≈ 2.0 × 10 3 kPa. The units are correct. 10.13 Analyze . Given: 760 mm column of Hg, densities of Hg and H 2 O. Find: height of a column of H 2 O at same pressure....
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This note was uploaded on 03/19/2008 for the course CHEM 102 taught by Professor Todd during the Spring '08 term at UNC.
 Spring '08
 Todd
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