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Module 1 - Experiment - Motion.pdf

Module 1 - Experiment - Motion.pdf - Module 1 Experiment...

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1/21/2018 Module 1 - Experiment - Motion http://www.webassign.net/web/Student/Assignment-Responses/last?dep=17865766 1/4 Current Score : 99.17 / 100 Due : Sunday, January 14 2018 11:59 PM EST Module 1 - Experiment - Motion (Lab) Twokoko Chaw PHYS 102 JAN 2018 Online, section Hanamean, Spring 2018 Instructor: J. R. Hanamean WebAssign The due date for this assignment is past. Your work can be viewed below, but no changes can be made. Important! Before you view the answer key, decide whether or not you plan to request an extension. Your Instructor may not grant you an extension if you have viewed the answer key. Automatic extensions are not granted if you have viewed the answer key. Request Extension
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1/21/2018 Module 1 - Experiment - Motion http://www.webassign.net/web/Student/Assignment-Responses/last?dep=17865766 2/4 1. 91.44/91.72 points | Previous Answers ERAUColPhysMechL1 2.1.IL.001. Use the exact values you enter to make later calculations. Part I: Data Part I: Questions Part II: Data Part II: Questions Complete Table 1. Record all data to three decimal places (e.g., 4.000 or 6.325 or 0.000). Do not include units in your answer. Table 1 Initial Settings At (m) Time (s) Calculated Position (m) Describe 20 4.000 20.000 Use Position ( x ) vs. Time graph increasing straight line 40 8.000 40.000 Use Velocity ( v ) vs. Time graph horizontal line 50 10.000 50.000 Use Acceleration ( a ) vs. Time graph horizontal line 20 2.000 20.000 Use Position ( x ) vs. Time graph increasing straight line 40 4.000 40.000 Use Velocity ( v ) vs. Time graph horizontal line 50 5.000 50.000 Use Acceleration ( a ) vs. Time graph horizontal line x = 0.00 m v = 5.00 m/s a = 0.00 m/s 2 d = vt . d = vt . d = vt . x = 0.00 m v = 10.0 m/s a = 0.00 m/s 2 d = vt . d = vt . d = vt . Please include units in your answer. Use the correct unit abbreviation. Include a space between the value and the unit. To express exponents in your units, use a ^. For example, m/s 2 would be m/s^2. By observing the Position vs. Time graph in Step 2 of the instructions, what physical quantity does the slope of this line correspond to? velocity (speed) The physical quantity is velocity (speed), as indicated in the Section 1.2 of the text. By observing the Position vs. Time graph in Step 2 of the instructions, what is the value of the slope of this line? 5 m/s Since the Position vs. Time graph is a straight line its slope corresponds to a constant velocity. By observing the Velocity vs. Time graph in Step 3 of the instructions, what physical quantity does the slope of the line correspond to?
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