ASE 211 Homework 2
1. Given the matrices
C
=
5
3
7
6
0

4
3
10
5
8
9

7
B
=
2
9
6

5
7

4
3
8
Multiply by hand
C
*
B
. Can you multiply
B
*
C
? Is it the same as
C
*
B
?
Compute
(
C
*
B
)
T
. Show that it is equal to
B
T
*
C
T
.
C
*
B
=

5
3
7
6
0

4

3
10
5
8
9

7
2
9
6
5
7

4
3
8
=
95
80
27
48
100

7
Can you multiply
B
*
C
? No,
B
is the wrong size. Hence
C
*
B
=
B
*
C
.
(
C
*
B
)
T
=
95
80
27
48
100

7
T
=
95
27
100
80
48

7
B
T
*
C
T
=
2
6
7
3
9
5

4
8
5
0
5
3

4
8
7
3
9
6
10

7
=
95
27
100
80
48

7
2. Given a column vector
d
=
2

5
7
3
Multiply
C
*
d
.
C
*
d
=
5
3
7
6
0

4
3
10
5
8
9

7
2

5
7
3
=
62
71
12
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Can you multiply
B
*
d
? No,
B
is the wrong size.
What about
B
T
*
d
? Yes.
3. Consider the 2x2 system
A
x
=
1

1

1
1
x
1
x
2
=
5

2
=
b
Does this system have a solution? No Solution exists
This is the end of the preview.
Sign up
to
access the rest of the document.
 Spring '08
 N/A
 Determinant, Matrices, Triangular matrix, lower triangular

Click to edit the document details