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Unformatted text preview: ASE 211 Homework 5 Solution Due: In class, Monday, October 11th. 1. By hand, compute the LU factorization, without row pivoting, of the following matrix: A = 6 3 1 3 1 0 2 2 4 . Check your result using the matlab lu function. Compute the first row of U and the first column of L . A = 6 3 1 3 1 0 2 2 4 = 1 1 / 2 1 1 / 3  6 3 1 u 22  . Now we compute u 22 = a 22 l 21 u 12 = 1 3 / 2 = 1 / 2 u 23 = a 23 l 21 u 13 = 0 1 / 2 = 1 / 2 a 32 = a 32 l 31 u 12 = 2 1 = 1 a 33 = a 33 l 31 u 13 = 4 1 / 3 = 11 / 3 These are the numbers that would be computed in the second column of A if we were doing Gaussian elimination on the first column of A . A → 6 3 1 3 1 0 2 2 4 = 1 0 0 1 / 2 1 0 1 / 3 l 32 1 6 3 1 1 / 2 1 / 2 u 33 ....
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 Spring '08
 N/A
 Numerical Analysis, Boundary value problem

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