9-5 - Section 2.8 E n+l= n+l= n+l= n+l= n+l= n+l= n+l= n+l=...

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Periodic Table Quantum Numbers in the Section 
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E 1 s 2 s 2 p 3 s 3 p 3 d 4 s 4 p 4 d 5 s 5 p 5 d 6 s 6 p 4 f 6 d 7 s 5 f Period 1 Period 2 Period 3 Period 4 Period 5 Period 6 Period 7 Per. p Per. p Per. p Per. p Per. p (Per. - 2)f (Per. - 2)f Per. s Per. s Per. s Per. s Per. s Per. s Per. s (Per. - 1)d (Per. - 1)d (Per. - 1)d (Per. - 1)d n + l = n + l = n + l = n + l = 6 7 7 7 8 n + l = n + l = 1 n + l = n + l = n + l = n + l = n + l = n + l = n + l = n + l = n + l = n + l = n + l = n + l = 2 3 3 4 4 5 5 5 6 6 7 8
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1 2 3 4 5 6 2 3 4 5 7 7 3 d 4 d 4 f 5 d Period s Period p (Period-1) d (Period-2) f 6 Section 
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s (2 groups) p (6 groups) 1 2 3 4 5 6 7 2 3 4 5 6 7 d (10 groups) f (14 groups) Section 
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+ E 1 s 2 p 3 p 3 d 4 s 4 p nuc leu 2 s 3 s Give the symbol of the neutral atom which could have this orbital occupation Section  Electron configuration of Si: Atomic number =14 1s2 2s2  2p6  3s2  3p2
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s p 2 3 4 5 6 7 1 2 3 4 5 6 7 d f Section  Si Si Electron Configuration:  1s2 2s2  2p6  3s2   3p2
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Electron configuration of Ge: Atomic number = 32 1s2 2s2  2p6  3s2  3p6  4s2   3d10  4p2 Give the symbol of the neutral atom which could have this orbital occupation Section  + E 1 s 2 p 3 p 3 d 4 s 4 p nuc leu 2 s 3 s
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Si s p 1 2 3 4 5 6 7 2 3 4 5 6 7 d f Section  Ge Electron Configuration: 1s2 2s2  2p6  3s2  3p6  4s2   3d10  4p2 G e
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Section  Elements in the same group on the Periodic  Table  have the same outer electron configuration! Summary
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This note was uploaded on 03/20/2008 for the course CH 101 taught by Professor Bigham during the Fall '08 term at N.C. State.

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9-5 - Section 2.8 E n+l= n+l= n+l= n+l= n+l= n+l= n+l= n+l=...

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