Discussion 7 key Fall 2007

Discussion 7 key Fall 2007 - 11. The sequence is ACACC...

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GENETICS (BIO 325) Fall 2007 Discussion 7 - Key _____________________________________________________________________________ _ 1. Carboxy-terminal – Arg Amino-terminal - Glu 2. Gene A – bottom strand Gene B – top strand 3. (a) Left (b) Upper 4. B 5. C 6. E 7. C 8. No. of bases Word size Number of combinations (a) 2 5 2 5 = 32 (b) 3 3 3 3 = 27 (c) 5 2 5 2 = 25 Note: The number of combinations must be 21 (20 amino acids and one stop codon). 9. (a) 3´-TACCTC. ........... GGGGTG-5´ 5´-ATGGAG. ........... CCCCAC-3´ (b) The top strand 3´ (c) Met—Glu—Ser. .................... Ser—Pro—His 10. (a) (1) The loops are introns. (2) (b) A mutation in the second intron prevents splicing, and no functional protein is made.
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Unformatted text preview: 11. The sequence is ACACC Since both of the mutations are probably caused by a change in a single base pair, one has to compare all the possible base pairs. Therefore the original Thr sequence is ACA. The amino acid is proline and it's sequence can only be determined unambiguously as far as the first two bases: CC. 12. (a) UUU UUA UUU UUA UUU UUA UUU UUA U phe -leu -phe -leu - phe -leu - phe -leu (b) UUU UAU UUU UAU UUU AUU UUU AU phe -tyr -phe -tyr - phe -ile - phe (c) UUU UUA UUU UUA UUU UAU UUU UAU phe -leu -phe -leu - phe -tyr - phe -tyr 2...
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Discussion 7 key Fall 2007 - 11. The sequence is ACACC...

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