Results and Discussion:
acid was reacted with a sample of a nitrite salt (5248), and various
measurements taken during and after this reaction were used to determine
the identity of the nitrite salt based on the following balanced chemical
reaction:
MNO
2(aq)
+ HSO
3
NH
2(aq)
MHSO
4(aq)
+ H
2
0
(l)
+ N
2(g)
Table 1: Data Used to Perform Calculations
Temperature of H
2
0 and N
2
24 ºC=297.15K
Mass of H
2
0
292.243 g
Atmospheric Pressure
756 mm Hg
Mass of Sample 5248
1 g
Density of Water
1 g/mL
3
The following calculations were performed in order to determine the identity
of the nitrite salt 5248 (MNO
2
) where M
+
could be Li
+
, Na
+
, K
+
, or Rb
+
.
This
preview
has intentionally blurred sections.
Sign up to view the full version.
First, using Dalton’s Law of Partial Pressures, (P
total
=P
H20
+ P
N2
), the pressure
of N
2(g)
was
determined, assuming that the total pressure was atmospheric
pressure and using the partial pressure of water at 24 ºC.
756 mm Hg= 22.38 mm Hg + P
N2
P
N2(g)
= 733.62 mm Hg
Next, the volume of N
2(g)
was found using the formula for density
(Density=mass/volume). The mass of the displaced water was used because

This is the end of the preview.
Sign up
to
access the rest of the document.
- Fall '05
- CHIRIK,P
- Chemistry, Mole, Reaction, Erlenmeyer flask, mm Hg
-
Click to edit the document details