labrreport2 - Results and Discussion: A sample of Aluminum...

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Results and Discussion:  A sample of Aluminum was synthesized to form a sample of Alum. After the  production of the sample was completed, the sample was allowed to dry for a week, at  which point its melting point and mass were determined in order to gage the purity of the  sample. The chemical equations showcasing the synthesis of Aluminum into Alum  follow: 1. 2Al (s) + 2KOH (aq)  + 6H 2 0 (l)  2K (aq)  + 2Al(OH)   4 - (aq)  + 3H 2(g) 2. 2Al(OH)   4 - (aq)  + H + (aq)    Al(OH) 3(s)  + H 2 0 (l) 3.  Al(OH) 3(s)  + 3H + (aq)   Al 3+ (aq)  + 3H 2 0 (l)  4. K (aq)  +Al 3+ (aq)  + 2SO 4 -2 (aq)  +12 H 2 0 (l)     KAl(SO 4 ) - 12 H 2 0 (s) Overall Reaction: 2Al (s)  +2KOH (aq)  + 4H 2 SO 4(aq)  +22H 2 0 (l)   2KAl(S0 4 ) 2  -12H 2 0 (s)  +3H 2(g)  
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Table 1 : Melting Point Ranges o Trial Melting Point Range (ºC)* 1 91 ºC -92 ºC 2 91 ºC -93 ºC 3 91 ºC -92.5 ºC 4 91 ºC -93 ºC Table 2 : Actual Yield versus Theoretical Yield of Solid Alum
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This note was uploaded on 03/20/2008 for the course CHEM 2070 taught by Professor Chirik,p during the Fall '05 term at Cornell University (Engineering School).

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labrreport2 - Results and Discussion: A sample of Aluminum...

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