Lecture 8.pdf - Mechanical systems Lecture 8 29-Feb-17 ME...

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Mechanical systems Lecture 8 29-Feb-17 ME 413: System Dynamics and Control: Dr Tesleem Asafa 1
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1. The problem is now dynamic with initial value, and time dependent parameters. 2. T is negative because it must act opposite to the direction of rotation to stop the shaft at 120s. So we want T at w(120). 29-Feb-17 ME 413: System Dynamics and Control: Dr Tesleem Asafa 2
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Obtain equivalent spring constant for each of the following systems: Force F is distributed on the 2 springs Same force F acts on each of the 2 springs 29-Feb-17 ME 413: System Dynamics and Control: Dr Tesleem Asafa 3
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Find the natural frequency of the system 29-Feb-17 ME 413: System Dynamics and Control: Dr Tesleem Asafa 4
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29-Feb-17 ME 413: System Dynamics and Control: Dr Tesleem Asafa 5
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29-Feb-17 ME 413: System Dynamics and Control: Dr Tesleem Asafa 6 1. The spring is massless, and it is not connected to any mass so m=0 2. The force F is applied to calculate the spring constant by creating an extension of 0.05m.
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