venn.docx - 1 n A)=n AB n A B = 14 12 =26 2 n B)=n B A n A...

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1. n ( A ) = n ( A B ) + n ( A∩ B ) = 14 + 12 = 26 2. n ( B ) = n ( B A ) + n ( A∩ B ) = 19 + 13 = 32 3. n ( U ) = n ( A B ) + n ( A ∩B ) 1 = { n(A) + n(B) + n ( A∩ B ) } + 14 = 13 + 15 + 11 + 14 = 53 4. n ( A∩ B ) = 11 5. n ( A B ) = n ( A ) + n ( B ) n ( A ∩B ) = (14 + 11) + (17 + 11) – 11 = 42 6. n ( A c ) = 18 + 17 = 35 7. n ( A∩ B c ) = ¿ Set elements belonging to both set A and set B c n ( A∩ B c ) = 15 8. n ( A B c ) = ¿ Set elements either in set A or set B c (including those which are in both) n ( A B c ) = 16 + 13 + 17 = 46 9. N(A) = 20 = 8 +12 N(B) =10 = 8 +2 N(U) = 40 = 12+8+2 +18 10. Because the identification code consists of two symbols, so: a. The first symbol is a letter (from A to B), so there are 2 choices, and 8 12 2 1
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b. The second symbol is a digit (from 1,2,3 and 4), so there are 4 choices. By multiplication principle, the permit can be issued by 2 x 4 = 8 ways. 11. The number of letters from A to J is 10 The number of numbers from 4 to 8 is 5 The number of total choices is, (no. of letters from A to J)+ (number of digits 4 to 8) =10 + 5 = 15 Because there are 7 slots, the number of possible passwaord will be: = 15 7 = 170,859,375 passwords.
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  • Summer '17
  • momanyi
  • Statistics, Natural number, Prime number

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