HWS02_C6_FARFAN.xls.xlsx - Problem 7.7 a Mean = Standard...

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Problem 7.7 a) Mean = Standard Deviation = n = Standard Error of the Mean = a. what is the probability that the X (Sample mean) Z Value P(X >19.5) Probability for X (sample me X (Sample mean) Z Value P(X < 20) between 19.5 and 20.5 = B. what is the probability that the Probability for X (sample mean) > X (Sample mean) Z Value P(X >0.19) Probability for X (sample mean) < X (Sample mean) Z Value P(X < 1) between 19.00 and 20.0 = Probability for X (sample me
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20 5.00 25 1.00 sample mean is between 19.5 and 20.5? 19.5 -0.5 0.30854 ean) < 20.5 20.5 0.50 0.6914625 0.38292 e sample mean is between 19 and 20? > 19 19 -1 0.2 < 20 20 0 0.50 0.3413447461 ean) > 19.5
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C) Mean = Standard Deviation = n = Standard Error of the Mean = C. what is the probability that the X (Sample mean) Z Value P(X >19.5) Probability for X (sample me X (Sample mean) Z Value P(X < 20) between 19.5 and 20.5 = d) Results in C has a less error bec Probability for X (sample me
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20 5.00 100 0.50 e sample mean is between 19.5 and 20.5? 19.5 -1.0 0.15866 ean) < 20.5 20.5 1.00 0.8413447 0.68269 cause the population are increasing, hence we have more values around the m ean) > 19.5
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mean. In A we have a gross error because the population is a quarter of C.
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P 7.15 Data CONDITIONS OF APLICATION n= 100 1.- n*π>5 π= 0.57 2.- n(1-π)>5 a.)If p=57 % or 0.57 % 0.57 Standard Error of proportion 0.0495075752 Z for sampling distribution 0 If Z==0 then Z table =0.5000 z= 0.5 b)If p are between 52 % and 62 %. Table Z. If P= 0.52 -1.0099464541 0.1562 Z for sampling distribution If P= 0.62 1.0099464541 0.8438 Table Z. If P= 0.62 1.0099464541 0.8438 Z for sampling distribution Probability fewer than 57 %.
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  • Spring '18
  • J.RR
  • 1%, 1 %, 0.0042174811 0.00421 g, 0.03 2.325 1.97675 Liters, 2.325 0.02 1.97675 Liters

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