This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 4.134. Find the 0point for the {rum in Fig. 4.80 if
1:... = HV. y =o.25 ﬂaw wn. = I0/l. 4.!33. Find the 0point fat the mistot in Fig$.81 if
”Urn : l V and wit.  [0/1. jollv 3mm
'4.ldl. "anew “42. 4.136. Find the Q~poim fat Ihe umiswt in Fig. 4.8! if
F”, = 3 V and. W1]. = 30H. M37. WhuiuheQpnimfar eachmisuinl’ig 4.82? HIV J +I2V +I:V
now I % mun
I "in?
L. W
.l. ”°"‘ I 1.2.
In) . (b)  dc; 
ﬁning.“
4.10 Current Sources and the MOS
Cm! Mirror “‘3
4.l38. Imﬁndlhc vaoinlforrhc minorin Fig. 4.68 . '
for n. = 1m. x, = 22 M9. n. a 240 m. 41“
R; = 0. and Vup I: I! V. Assume Ilia! Vm =
!V.y .. o.audwu_ = 15/1.(bmepmir
2’ = 0.6 JV.
4.139. Find the 0point to: a: minor in Fig. 4.63:» 4 “5
rork.430kn.n,noka.k,=o. 2
R. a I20kﬂ.andvpp c I2V. Assumcthu
Vrn = —l V. y = 0. and W/L = I0/l.(b) RG
pcat if y = 0.75 JV 4.146.
4.140. The depletionmod: mosm in Fig. 4.83 is an 3:
be used as a cum: scum. m minim: has 4.!41.
wn. = 15/1. v". a —5 Mandy = awn: '5 PM Figurl 4.83 vluofkisrequitedmseimecmnnuo 100M?
What is the minimum “In: for V? nep‘ea: mu. 4.14m” = 0.5 ﬂ. Wmdummlcumtsmdmwmimes
for the cutmm sources in Fig. 4.84 if I.” :
30M. K1: 25 W3. V”, a 0.75 V. and
A  (LOIS V"? "We .84 Whatistheminimmn vnlueofvps need'edmsm~
um: transistor M4 in Prob. 4.!42? Whmmtheoinpmcnmtsandmtpultuis
mfulbecunenlsoumesinﬁgJﬁﬁfR =
30m. K}.=IS W3.V1ps0.90Vandk=
0.0IV"? WMuofRianuimdin Fig.4.85tohave
log = 35 M? Use device dam hum Prob. 4. M4.
\th is the minimum value of Vp; requimd to
W M3? . Simulaie the cutter“ some: may in Prob. 4.”:
and compare the malls lo the hand calculation; Simulate the curem we: may in Prob. 4.144
and compare the. mum to the hand calculations. +5 v v
R
—5 V 2" IO V
Figure $.36 Figure ..87 4.156. Find me oilresistance of the JFET in Flg. 4.88
“In” =1“!!!de = 5VR¢P¢3f0t 4.148. (I) A minorhu 1‘. = 40m, V" a l V. '05: . lOOpAande =2V. mngcmZNgLszpm.andW=20m Wham x.. andmesatunwd vnluc ofipfor um: ”V
Innsiswl if v6, = 4 V? m m mummy is '06
sukdbylfacmofz.mnmen¢wvaluesof
Tun W 11 VT!“ VGSI Knuth? J10 ‘
4M9. (a) A mam: has In mid: thickness or 20 m  7 V:
wimLlpmlndw=20pm.Whniscacfor «2.. ,
his mansiswﬂ (b) The wchnology is scaled by a
Morofl.Whmuedemvﬂmaf1‘w W.L.
MC“?
. mung.“ Hutu.”
4.150. Show thumccumﬁﬁeqnalcydal’MOSdemc
ii gimby f7 = 553W“  an. L157. The Jf‘ET in Fig. ‘39 has [935 = l IDA I“
4.151. (a) An mos device in: u.  400 mm . s. V» = 4 V. ma la. la. and V: formmif
wathcmnoﬁﬁeqmyfuLalumifme midﬁmmmldm
umn'smrisbiaSedlt l V mmﬂdﬂw “158. The IFETS in Fig. 4.90 have [953. = 200 M.
wouldbelhemoﬂﬁeqmmyofuimimmos Vpll—2V.Inm=SW‘ .anan=—6V.
devioc'du, = 0.411.?(bmcpeltforl. = 0.1m. (I)Findl.heQpoint formetwolFEl'sifV =9V
4.152.MNMOSWMSTM=80MLL.= (b'JWMIislheuﬁnimumvaluGOfVMwm
400cm’N'i.L=0.mW=25mlodvas— cusumhnbothlundhateinphdmm
v". = 2 v.mw1m Lulu: ammion ngioncur «.159. The Jam int1g. 4.91 have (m = mum»!
rem pmdicwd by Eq. (4J9)? (b) Whll is the smu Vp = +2 V. (a) FlndtthpoinlfunhetwoJIEﬁ
mloncumlp‘edicnedby 51144.88“wa v
Us” :3 IO.' CID/37
4.153. 111: NMOS (amino! in Hz. 4.44 is biased with R
Vas=0V.Whuisdechincmuﬁ'(b)Whalis V
dudninmifﬂwmlnldvnlngcisredmed
loOJV’.’ 1: In
“2me mamwumn m“
4.154. The JET in Fig. 4.86 has I"; = 500 M and J 12
V, s 3 V. Find lhc 0point for the NET fox ‘ ' mm (a)R=0deSSV(b}R=0andV =0.25V,
and(c)R=8.2lendV =5V. 4.155. Find the Win! fot the JFET in Fig, 4.81 if ’
’03.: = 5 mA and V, a: —5 V. Flynn.” “gum”: ...
View
Full Document
 Spring '12
 cengizbeşikçi
 vaoinlforrhc minorin Fig., Q~poim fat Ihe, dam hum Prob., V. ma la., wouldbelhemoﬂﬁeqmmyofuimimmos Vpll—2V.Inm=SW‘ .anan=—6V

Click to edit the document details