current-mirror-problems.pdf

# current-mirror-problems.pdf - 4.134 Find the 0-point for...

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Unformatted text preview: 4.134. Find the 0-point for the {rum in Fig. 4.80 if 1:... = HV. y =o.25 ﬂaw wn. = I0/l. 4.!33. Find the 0-point fat the mistot in Fig-\$.81 if ”Urn :- -l V and wit. - [0/1. jollv 3mm '4.ldl. "anew “42. 4.136. Find the Q~poim fat Ihe umiswt in Fig. 4.8! if F”, = -3 V and. W1]. = 30H. M37. WhuiuheQ-pnimfar eachmisuinl’ig 4.82? HIV J +I2V +I:V now I %- mun I "in? L.- W .l. ”°"‘ I 1.2. In) . (b) - dc; - ﬁning.“ 4.10 Current Sources and the MOS Cm! Mirror “‘3- 4.l38. Imﬁndlhc vaoinlforrhc minorin Fig. 4.68 . ' for n. = 1m. x, = 22 M9. n. a 240 m. 4-1“- R; = 0. and Vup I: I! V. Assume Ilia! Vm = !V.y .. o.audwu_ = 15/1.(bmepmir 2’ = 0.6 JV. 4.139. Find the 0-point to: a: minor in Fig. 4.63:» 4- “5- rork.-430kn.n,-noka.k,=o. 2 R. a I20kﬂ.andvpp c I2V. Assumcthu Vrn = —l V. y = 0. and W/L = I0/l.(b) RG- pcat if y = 0.75 JV 4.146. 4.140. The depletion-mod: mosm in Fig. 4.83 is an 3: be used as a cum: scum. m minim: has 4.!41. wn. = 15/1. v". a —5 Mandy = awn: '5 PM Figurl 4.83 v-luofkisrequitedmseimecmnnuo 100M? What is the minimum “In: for V? nep‘ea: mu. 4.14m” = 0.5 ﬂ. Wmdummlcumtsmdmwmimes for the cut-mm sources in Fig. 4.84 if I.” :- 30M. K1: 25 W3. V”, a 0.75 V. and A - (LOIS V"? "We .84 Whatistheminimmn vnlueofvps need'edmsm~ um: transistor M4 in Prob. 4.!42? Whmmtheoinpmcnmtsandmtpultuis- mfulbecunenlsoumesinﬁgJﬁﬁfR = 30m. K}.=IS W3.V1ps-0.90Vandk= 0.0IV"? WMuofRianuimdin Fig.4.85tohave log = 35 M? Use device dam hum Prob. 4. M4. \th is the minimum value of Vp; requimd to W M3? . Simulaie the cutter“ some: may in Prob. 4.”: and compare the malls lo the hand calculation; Simulate the cur-em we: may in Prob. 4.144 and compare the. mum to the hand calculations. +5 v v R —5 V 2" -IO V Figure \$.36 Figure ..87 4.156. Find me oil-resistance of the JFET in Flg. 4.88 “In” =1“!!!de = -5V-R¢P¢3f0t 4.148. (I) A minorhu 1‘. = 40m, V" a l V. '05: . lOOpAande =-2V. mngcmZN-gLszpm.andW=20m Wham x.. andmesatunwd vnluc ofipfor um: ”V Innsiswl if v6, = 4 V? m m mummy is '06 sukdbylfacmofz.mnmen¢wvaluesof Tun W- 11- VT!“ VGSI Knuth? J10 ‘ 4M9. (a) A mam: has In mid: thickness or 20 m - 7 V: wimL-lpmlndw=20pm.Whniscacfor «2.. , his mansiswﬂ (b) The wchnology is scaled by a Morofl.Whmued-emvﬂmaf1‘w W.L. MC“? . mung.“ Hutu.” 4.150. Show thumccumﬁﬁeqnalcydal’MOSdemc ii gimby f7 = 553W“ - an. L157. The Jf-‘ET in Fig. ‘39 has [935 = l IDA I“ 4.151. (a) An mos device in: u. - 400 mm . s. V» = -4 V. ma la. la. and V: formmif wathcmnoﬁﬁeqmyfuLalumifme midﬁmmmldm umn'smrisbiaSedlt l V mmﬂdﬂw “158. The IFETS in Fig. 4.90 have [953. = 200 M. wouldbelhemoﬂﬁeqmmyofuimimmos Vpll—2V.Inm=SW‘ .anan=—6V. devioc'du, = 0.411.?(bmcpeltforl. = 0.1m. (I)Findl.heQ-point formetwolFEl'sifV =9V 4.152.MNMOSWMSTM=80MLL.= (b'JWMIislheuﬁnimumvaluGOfVMwm 400cm’N'i.L=0.|mW=25-mlodvas— cusumhnbothlundhateinphdmm v". = 2 v.mw1m Lulu: ammion ngioncur- «.159. The Jam int-1g. 4.91 have (m = mum»! rem pmdicwd by Eq. (4J9)? (b) Whll is the smu- Vp = +2 V. (a) Flndtth-poinlfunhetwoJI-Eﬁ mloncumlp‘edicnedby 51144.88“wa v Us” :3 IO.' CID/37 4.153. 111: NMOS (amino! in Hz. 4.44 is biased with R Vas=0V.Whuisd|echincmuﬁ'(b)Whalis V dudninmifﬂwmlnldvnlngcisredmed loOJV’.’ 1: In “2me ma-mwumn m“ 4.154. The JET in Fig. 4.86 has I"; = 500 M and J 12 V, s -3 V. Find lhc 0-point for the NET fox ‘ ' mm (a)R=0deSSV(b}R=0andV =0.25V, and(c)R=8.2lendV =5V. 4.155. Find the Win! fot the JFET in Fig, 4.81 if ’ ’03.: = 5 mA and V, a: -—5 V. Flynn.” “gum”: ...
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• Spring '12
• cengizbeşikçi
• vaoinlforrhc minorin Fig., Q~poim fat Ihe, dam hum Prob., V. ma la., wouldbelhemoﬂﬁeqmmyofuimimmos Vpll—2V.Inm=SW‘ .anan=—6V

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