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Ch. 14 Problems.pdf

Ch. 14 Problems.pdf - Questions-— Chapter 14 Continued K...

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Unformatted text preview: Questions -— Chapter 14 Continued K 1. What is the principle of detailed balance? 6) €61 V. = V '1 2’” 6 E3. C + D talc; kl (A32 (5] (ale = L‘ (6] [D] 2 The compound IrH3(CO)(P(C6H5)3) exists in two forms: the meridional (mer) and the facial (fac). At room temperature in a non-aqueous solvent, the reaction mer 9 fac has a rate constant of 2. 33 s" ,and the reaction fac 9 mer has a rate constant of 2.10 s . What IS the equilibrium constant of the reaction mer 9 fac at room temperature? |_ ‘ 3 Write the overall reaction and the rate laws that correspond to the following mechanisms. Be sure to eliminate intermediates from the answers: D -S \Aieumthl'C, b/C' .L \S (Vodutrtl I COV‘SUMA a. 2A + B <-> ,5 (fast equ111bnum) @D’ + B a E + )7’ (slow) Me 0‘ rm: e2 [0] E63 ,1? 9 G (slow) (P b. A + B s Q)? (fast equilibrium) C + D <-> F (fast equilibrium) F 9 G (slow) 4. HCI reacts with propene (CH3CHcI-12) according to HCl(g) + CH3CHCH2(g) 9 CH3CHCICH3(g) The experimental rate law IS rate- — k[HCl]3 [CH3CHCH2] Which if any, of the following mechanisms are consistent with the observed rate law? . HCl + HCl <—> H + HCl2 (fast equilibrium) H + CH3CHCH2 9 CH3CHCH3 (slow) HCl2 + CH3CHCH3 9 CH3CHC1CH3 +HC| (fast) @HCI + HCl <—> H2 + Cl2 (fast equilibrium) HCl + CH3CHCH2 <-> CH3CHCICH3* (fast equilibrium) CH3CHCICH3* + HZCl2 9 CH3CHClCH3 +2HCl (El/01v) /c./HC1 + CH3CHCH2 <-> H + CH3CHCICH2 (fast equilibrium) H + HCI e HZCl (fast equilibrium) No‘e HZCl + CH3C1-IC1CH2 9 HO + CH3CHC1CH3 (slow) 0%" 5. The reaction N(SOa)32 (aq) + H 0(1) —> mason; (aq) + HSO4(aq) C ’2: follows the rate law rate: twinfzsoa)3 ][H*] The rate increases by a factor of 23.1 when the temperature is raised from M1: In A "21:“ 283K to 313K. Compute Ea for the reaction. ,Qfih :flv‘A' é(%'\ -,Ea __ l oflkz-QAL' " T ( 42, '17:) L3.) (D lg (A31 Cs}: @ch Co] _l_£_'__ __ [C3 C03 K WM MVQX LONE,“ RKN ;v\\~vw~—a.oL-o.-Lcs_ k—I (A31 [a] ‘ 5.- 3a (ALL: k2 (DJ Kg) K‘ = k,. (I: [DJ KC 1 (01(6) a CD): A3 C6] k k ‘ \ Z ' my E63 { “MW—M7 b. rMcz-QEF'] —7 51$; [c.1033 -—-% wCBJE61[D3 K-Z K—‘ZKq k £53. 1: CCJED CF): K2 CC] (03 46. ML“ u'uzcfl CCH CH6! (”1] A J i Mk 7 kQ/jfum‘g (McQCCI43w 04;? V5 mic : {c GHQ—L (“’5‘ “(all b- VOJ'L-z/k [NLCIZBKCIJSC'LI “(H-53 rate; {5 [Hafiz] ("'Cl) (C145(L>cua] («Ltzk [HLf—JZCHL‘BCC pscuculj ...
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