math statistics special assignment for sect 7.3 and 7.4.docx

math statistics special assignment for sect 7.3 and...

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Matthew Molina MAT 150 Special Assignment for Sections 7.3 and 7.4 1) An insurance company checks police records on 582 accidents selected at random and notes that teenagers were at the wheel in 91 of them. Create a 98% confidence interval for the percentage of all auto accidents that involve teenage drivers and write a sentence that interprets the interval. pp = X/ n = 91/582 = .156 = .16 q ^ = 1 - pp = 1.00 - .16 = .84 α = 1 - .98 = .02 α /2 = .02/2 = .01 z α /2 = 2.33 Formula pp - z α /2 q pp ^ / n < p < pp + z α /2 q pp ^ / n = .16 - 2.33 (.16)(.84)/582 < p < .16 + 2.33 (.16)(.84)/582 = .16 - .035 < p < .16 + .035 = 0.125 < p < .0195 = 12.5% < p < 19.5% One can be 98% confident that the percentage of accidents involving teenagers at the wheel is between 12.5 and 19.5%. A politician urging tighter restrictions on drivers’ licenses issued to teens says, “In one of every five auto accidents, a teenager is behind the wheel.” Does your confidence interval support or contradict this statement? Explain. My confidence interval contradicts this statement because worse case scenario the percentage of accidents involving teenagers well be 19.5% which is less then 1/5 or 1 of every 5.
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  • Spring '16
  • muhammad sami
  • Special assignment, healthy adults, Matthew Molina

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