tugas 2.docx - BAB 6 1 A 2 Diketahui tawaran investasi X...

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BAB 6 1. A 2. Diketahui : tawaran investasi X $6.000/thn selama 9 thn Tawaran investasi Y $8.000/thn selama 6 thn Ditanay : nilai sekarang yg lebih tinggi dengan bunga diskonto 5% dan 15% Jawab : Pv. X = F x (1 + i ) -n X1 = 6.000 x 1,05 -1 = 5.714 X2 = 6.000 x 1,05 -2 = 5.442 X3 = 6.000 x 1,05 -3 = 5.183 X4 = 6.000 x 1,05 -4 = 4.936 X5 = 6.000 x 1,05 -5 = 4.701 X6 = 6.000 x 1,05 -6 = 4.477 X7 = 6.000 x 1,05 -7 = 4.264 X8 = 6.000 x 1,05 -8 = 4.061 X9 = 6.000 x 1,05 -9 = 3.868 Total nilai X jika i = 5% adalah $42.646 Pv. Y = F x (1 + i ) -n Y1 = 8.000 x 1,05 -1 = 7.619 Y2 = 8.000 x 1,05 -2 = 7.256 Y3 = 8.000 x 1,05 -3 = 6.911 Y4 = 8.000 x 1,05 -4 = 6.582 Y5 = 8.000 x 1,05 -5 = 6.268 Y6 = 8.000 x 1,05 -6 = 5.970 Total nilai Y jika i = 5% adalah $40.606 Jadi Nilai sekarang yang paling tinggi jka i= 5% adalah penawaran dari PT X Pv. X = F x (1 + i ) -n X1 = 6.000 x 1,15 -1 = 5.217 X2 = 6.000 x 1,15 -2 = 4.537 X3 = 6.000 x 1,15 -3 = 3.945 X4 = 6.000 x 1,15 -4 = 3.431 X5 = 6.000 x 1,15 -5 = 2.983 X6 = 6.000 x 1,15 -6 = 2.594 X7 = 6.000 x 1,15 -7 = 2.256 X8 = 6.000 x 1,15 -8 = 1.961 X9 = 6.000 x 1,15 -9 = 1.706 Total Nilai sekarang X jika i= 15% adalah sebesar $28.630 Pv. Y = F x (1 + i ) -n Y1 = 8.000 x 1,15 -1 = 6.957 Y2 = 8.000 x 1,15 -2 = 6.049 Y3 = 8.000 x 1,15 -3 = 5.260 Y4 = 8.000 x 1,15 -4 = 4.574 Y5 = 8.000 x 1,15 -5 = 3.977 Y6 = 8.000 x 1,15 -6 = 3.459
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Total Nilai sekarang Y jika i= 15% adalah sebesar $30.276 Jadi Nilai sekarang yang paling tinggi jika i= 15% adalah penawaran dari PT Y 3. Nk 4. Diket : suatu investasi menawarkan penerimaan kas $5.300/thn slama 5 thn. Pembayaran pertama satu tahun dr sekarang Imbal hasil 7% Ditanya: a. Nilai investasi b. Nilai pembayaran 40 tahun c. Nilai pembayaran 75 tahun d. Nilai pembayaran selamanya Jawab: a. Nilai investasi
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