This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 163818qz5a > sec. __ name: hi; 3?. 3m [Useful information: E=l_1_c_:; h=6.626 x 10'34 J—s; c=3.00 x 108 m; 1 J = 6.24 x 1018 electron—volts
7» s ' . . 1. (3 pts) This problem has SIX parts. Use the periodic table provided on the reverse side to help you to complete these questions about ﬂuorine.
a. (0.5 pt) Complete the following energy level diagram for ﬂuorine. Show the number of electrons expected in each energy level. If there are no electrons in an energy level, leave it blank.
w, my; 1 MKS \H O )‘Ze.’ )de‘ ) )
q n=l n=2 11:3 n=4 ,
b. (0.5 pt) Determine the number of valence electrons for ﬂuorine. :i‘
c. (0.5 pt) A neutral atom of ﬂuorine will either gain or lose e's to form an _I__0_Z__V that has the same number of electrons as which noble gas? N6. .
l' d. (0.5 pt) Complete the energy level diagram for a ﬂuoride ION. Show all electrons.
i .
0 >26. ) 54¢ ) ) n=1 n=2 n=3 n=4
‘ e. (0.5 pt) What is the charge on the ﬂuoride ION? Please circle your answer below. 4 3 —2 ® 0 +1 +2 +3 +4 . f. (0.5 pt) Please answer this question based on your answer to (e). Wh1ch is LARGER: a neutral ﬂuorine atom or @ Please circle your choice.
W4 F SacvwJt OV‘Q C" JW WM Elf—i 2. (2 pt) A H electron moves from energy level n=5 to n=4. Use the diagram below to answer the questions. n=5 ‘ 14.1 eV
‘ n=4 13.8 eV fl;
n=3 13.1 eV n.=2 11.2 eV a. (0.5 pt) When an electron moves IEROM energy level n=5 T 0 n=4l, is energy ( absorbed or )? Please circle your answer. Pb. (0.5 pt) Please explain. PLEASE PRINT. 5‘15.
W (“W Almfa “\7’; C\ lower E laud; E WHAS’l" ‘01 “magici c. l t Calculate the number of electron volts that are absorbed/released when an electron moves
ROM energy level n=5 T 0 n=4. Please Show how youarrive at your answer (no work=0.25 pt). Mi: E? E“ a mav— wev: <73 03 av A box. " 3. (2 pt) The energy, E, of the electron moving WOM energy level n=4 T 0 n=3l is 4.76 x 10‘19 J.‘ Find the
wavelength of the light in units of nanometers. Please use the “gﬁc” approach and show all of your work for full
credit. Just a numerical answer without showing work will earn you 0.25 point. . _ _ .14) Lower 'E LLUL
4. (3 pts) Please complete the following table about names and formulas for polyatomic 1on5. ls energy released or absorbed? "HIM—S are, 3‘! '15 MMSZJ< Elva/1‘0)“ WULh 90W Magnum Given the formula, write the name. I
d. canoe1 mate 6. 8042 Sud Rial—C f. NHL;+1 mmvwgvuium l / Given the name, write the ﬂmula, including :1: char e.
_ a. phosphate Pﬁf
b. nitrate N 0 2 ," c. cyanide CN ’4 extra credit: (1 pt) You may ﬁnd it useful to look at the energy level diagram for quiz question #2 to answer
these questions. Eamon A moves from n=4 to n=3 ; leLectron B moves rom n=4 to n=2. Each transition emits light of a
different color. Please answer the following questions about A and B. .,
a..(0 25 pt) For which electron is MORE energy released, electron A or electron B? B b. (0.25 pt) For which electron is the light released of LONGER wavelength, (( electron A > or electron B )? l Please circle your answer.
c. (o 5 pt) How do you know? PLEASE PRINT. ﬂows r 4%. may WSWRrA/L; waive/1043” «HA4 LOW W W137) MlOVWWwwc’l—uﬁl—l’x 1 Periodic Table of the Elements 2A  3A 4A 5A 6A 7A
14 1 5 6 7 B 9 10 1 1
24 25 26 27 28 29 30 1
Cr Mn Fe Co Ni CU Zn _ a
52.0 54.9 55.8 58.9 58.7 63.5 65.4 28 . . . .
42 43 44 45' 46 47 48 50 S1 52 53 54
Mo Tc Ru Rh Pd Ag Cd Sn Sb Te 
2.9 95.9 (9 8) 101 103 106 108 112 181n5 119 122 128 127 13:1
56 72 74 75 76 '77 78 79 BO 82 883I 84 55
(:5 Ba Hf W 05 Ir Pt Au H 2Pb Ato
133 137 1::9178 1831 184 1R1; 190 192 195 197 88 10f4 105 106 107 108 109 110
Db 89 8h Hs Mt
2267 (262) (262) (263) (2 ) (265) (266 (281) (223) 226 163818qz5b sec. name: Keg} 9&2 5 lo .
.r . d
Useful information: E=h_c; h=6.626 x 10'34 J—s; c=3.00 x 108 m; l J = 6.24 x 1018 electron—volts J
A. ~ . s =1. (3 pts) This problem has SIX parts. Use the periodic table provided on the reverse side to help you to complete these questions about oxygen. ‘ .
a. (0.5 pt) Complete the following energy level diagram for oxygen. Show the number of electrons expected in each energy level. If there are no electrons in an energy level, leave it blank. le WK}?
0 )26 )u; ) )
. ‘ n=l n=2 11:3 , n=4 .
b. (9.5 pt) Determine the number of valence electrons for oxygen. (0 c. (0.5 pt) A neutral atom of oxygen will either gain or lose e‘s to form an ION that has the same number of electrons as which noble gas? N35
d. (0.5 pt) Complete the energy level diagram for an oxide ION. Show all electrons.
0 )Z6 >36 ) )
n=1 . n=2 n=3 11:4 e. (0.5 pt) What is the charge on an oxide ION? Please circle your answer below. —4 —3 ® —1 p 0 +1 . +2 +3 +4 , f. (0.5 pt) Please answer this question based on your answer to (e) . NVhich is larger, a neutral oxygen atom or 2. (2 pt) A H electron moves [EROM energy level n=4 T 0 n=2l Use the diagram below to answer the
5; questions. n=5 14.1 eV
n=4 13.8 eV 9
n=3 13.1 eV =2 11.2 eV _ (a. (0.5 pt) When an electron moves [FROM energyjevel n=4 T 0 n= , is energy . ( absorbed 01"? Please circle your answer.
b. (0.5 pt) Please explain. PLEASE PRINT.
‘1 1W ELM/WW (“L098 94:va a. “SAW {7; alum/{Ar 0/»:wa hora/i; Wv'mﬁalgk mmmcl 0. gm) Calculate the number of electron volts that are absorbed/released when an electron moves
ROM energy level n==4 T0 11:2} Please show how you arrive at your answer (no work=0.25 pt). Ari? ErrE11 \LzaInnzV = @240 {JV ‘5 i0
3. (2 pt) The energy, E, of the electron moving FROM n=5 T0 n=3 is 1.60 x 10'19 J. Find the wavelength of the light in units of nanometers. Please use the “gfu” approach and show all of your work for ﬁill credit. Just a
numerical answer without showing work will earn you 0.25 oint. a? 18 energy released or absorbed? 4. (3 pts) Please complete the following table Given the formula, write the name. 4 0211302" $2217.12 b. carbonate c. hydroxide extra credit: (1 pt) You may ﬁnd it useful to'look at the energy level diagram for quiz question #2 to answer
these questions. lectron A moves ram n=5 to n= ' iglectron B moves from n=5 to n= 31. Each transition emits light of a different color. Please answer the following questions about A and B.
a (0. 25 pt) For which electron 18 MORE energy released, electron A or electron B? B b. (0. 25 pt) For which electron is the light released of LONGER wavelength, ( or electron B )?
Please circle your answer. c. (0.5 pt) How do you know? PLEASE PRINT 4192. iriCﬂi/tev W My 1 WW% walnut
\WHA
‘i’iM. lower (”he W11 «Ha/WM W‘Vue/LQUW >i=>14=l=>l<$*****>i==1:***=i=5k*>i<>i=*>i<****************=i<*****>l=******>i==14>i<****>l=******************************* Periodic Table of the Elements 3A
13 4A
l4 5A
15 6A 9 10 11 12 
24 25 26 27 28 29 30 31 32 33 34 35
Cr Mn Fe Co Ni CU Zn Ge As Se Br
2. 54.9 55.8 58.9 58.7 63.5 654 5927 726 749 79.0 79.9
42 43 45 4e 47 4850 51 52 53
Mo Tc Rh Pd Ag Cd Sn Sb Te I
. . . 959 (98) 1E1: 103 106 108 112 115 19 122 128 127
74 75 77 78 79 80 82 83 84 85 86
W Re Ir Pt Au TI Bi Po At Rn
133 137 139 178 1T881 184 186 1%30 192 195 197 204 207 209 (209) (210)(222) 9 1&10135 1 6 107 1058 109 1010
c 59 811
63) (262) (2655) (266 (20851) 201 O Rf) (20:2) (2 163s18qz5c  sec. __ name: Kg” %2 SC. ‘ Useful information: E=h_Q; h=6.626 x 10‘34 Js; c=3.00 x 108 m; 1 J = 6.24 x 1018 electronvolts 1» 1. (3 pts) This problem has SIX parts. Use the periodic table provided on the reverse side to help you to complete these questions about nitrogen. .
a. (0.5 pt) Complete the following energy level diagram for nitrogen. Show the number of electrons
expected in each energy level. If there are no electrons in an energy level, leave it blank. Vikki; 2. WKK :3
0 _)2e )Q: ) l
. n=2 11:3 n=4
b. (0.5 pt) Determine the number of valence electrons for nitrogen. 5
c. (0.5 pt) A neutral atom of nitrogen will either gain or lose e's to form an ION that has the same number of electrons as which noble gas? Na
d. (0 5 pt) Complete the energy level diagram for a nitride I_Q__N. Show all electrons.
0 )AE )ta ) )
n=1 n=3 n=4
e. (0.5 pt) What is the charge on a nitride ION? Please circle your answer below. —4 GD —2 1 0 +1 +2 +3 +4 f. (0.5 pt) Please answer this question based on your answer to (e) . " Which is LARGER: ( aneutral nitrogen atom or nitride ION )? Please circle your answer.
11‘: _ 2. (2 pt) A H electron moves ROM ener level n=5 T 0 n= . Use the diagram below to answer the questions. n=5 14.1 eV
n=4 13.8 eV
n=3 13.1 eV
n=2 11.2 eV a. (0.5 pt) When an electron moves ROM ener level n=5 T O n= , is energy Wt b. (0.5 pt) Please explain. PLEASE PRINT. lambilwi‘wxguii mpg WQ MW {73 a, WWW LUNA? W7 own/Si“ QC. 1 t Calculate the number of electron volts that are absorbed/released when an electron moves
ROM ener level n=5 (TO n= Please Show how you arrive at your answer (no work=0.25 pt).
ALE: EVE" QiixleV~1LL1€U : Q 23er 3.; 3. (2 pt) The energy, E, of the electron moving_ FROM n=4 TO n=2 is 4.17 x 10~19 J. Find the wavelength of the
light in units of nanometers. Please use the “gﬁt” approach and show all of your work for full credit. Just a
numerical answe1 without showing work will earn you 0 25 point 8‘ E2 Li'x‘?‘>§[0"la(j >\ XIO WW;
5;: /\
ml Elbe;
X >\
EX‘ l/\C
>\':L ler.
' E . Given the formula, write the name. .2 a nitrate d. C03;2 waai—e C. N " f. (:sz0. Mex—axe extra credit; (1 pt) You may ﬁnd it useful to look at the energy level diagram for quiz question #2 to answer
these questions. c. cyanide Electron A moves from n=4 to 11:3; electron B moves from n=5 to n=3. Each transition emits light of a different color. Please answer the following questions about A and B.
a. (0.25 pt) For which electron is LESS energy released: (( electron E) or electron B )? Circle your answer. b. (O 25 pt) For which electron is the light released of SHORTER wavelength ( electron A or( electron B 2)?
Please circle your answer. c. (0. 5 pt) How do you know? PLEASE PRINT flu. likaMw 44M QWEW 44M glncwkm .HM weave
lﬁl/L “A
3
m \OMV‘ W game/5V l 44% km” Hnwﬁuﬂ‘ ********** *****4=*****vl<3l’*>l'*$***vl<**=l=l=l**ﬁ’****ad?*******‘:>>l~****>l~********$*******+*$***>§~****$*** Periodic Table of the Elements 3A 4A
l3 l4 (223) 226...
View
Full Document
 Spring '08
 CHRISTINABONACCORSI
 Chemistry, Electron, Periodic Table

Click to edit the document details