Wireshark TCP Lab.pdf - Wireshark TCP Lab 1 Source IP...

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Wireshark TCP Lab 1. Source IP: 192.168.1.102 a. Port Number: 1161 2. Destination IP: 128.119.245.12 a. Port Number: 80 3. IP address: 192.168.0.17 a. Port Number: 50106 4. Sequence number: 0 a. SYN Flag is 1, this indicates a SYN segment 5. SYNACK sequence number: 0 a. ACK value: 1 b. ACK value is determined by adding 1 to the client computers initial sequence number of the SYN segment c. SYN and ACK flag are 1
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6. Segment 4 Sequence number: 1 7. First 6 TCP segments are 4,5,7,8,10,11 a. Times are: i. 9:44:20.596 ii. 9:44:20.612 iii. 9:44:20.624 iv. 9:44:20.652 v. 9:44:20.647 vi. 9:44:20.648 b. ACK receipt times: i. 9:44:20.6243 ii. 9:44:20.6476 iii. 9:44:20.6944 iv. 9:44:20.739 v. 9:44:20.787 vi. 9:44:20.838 c. RTT after each ACK: i. 0.0283 ii. 0.0356 iii. 0.0704 iv. 0.087 v. 0.14 vi. 0.19 d. ESTIMATEDRTT after each ACK: i. 0.0283 ii. 0.0292 iii. 0.03435 iv. 0.04093 v. 0.05331 vi. 0.07041
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8. Length of first TCP segment: 565 a. Length of other TCP segments: 1460 9. minimum amount of available buffer space advertised: 5840 a. sender is never throttled due to lack of receiver buffer space 10. No, there are no retransmitted segments. By checking the sequence numbers of the TCP
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  • Fall '14
  • Zau
  • Transmission Control Protocol, sequence number, a. port number

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