Midterm2 - Solutions.pdf - 1(16 pts The position of an...

Info icon This preview shows pages 1–6. Sign up to view the full content.

Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

Image of page 2
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

Image of page 4
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

Image of page 6
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1. (16 pts) The position of an asteroid at time t > 0 is given by \ 77(75)— — e i+2€ sintj +26 cost/c :75, t<2/2 (7272/2; 257727 2,} (a) (3 pts) Verify that the asteroid’s Speed, as a function of t, is 36. Uzi/K2222 622/2U U222 V2272: 32<2 2/2/2227 2272727> ,2 ._//‘ /2 2H),) 7 1/ 2222/ (72’1“ 2 ///I/H 2/7717 250.42, 27/75/2732; jam/227 22172251? 252722 27-2-2227/712 / ((2727 2/2 (202/747 ’ -,:7///I 2 “MM A.,;,,W,nfl,.. r ,,,.,,,7,“:, ‘,,,,L “.777, , I /yfijr_w (l / f . I j "I 7;; (I: 2 21227-- 7 __7 </ - I /- ,1 222,277,- I, 2 24/727 2, “272-2 «2/72,, I 2 272/2” 2 1. 212/ 2 r 7257 7 775, a, ”97”,” 2 4/w / A 4/1 2/} 22M 2 2 2 (2 1:: ’3‘; 2 1/ (b) (2 pts) Find the arc-length, as a functiOn of time t, of the asteroid’s path from t— — —oo to time t. 7 / fl 2’2? {7 j) , I71 7" / I; 2 27' 7222 :1“ 2 22 $222222” ~79; f 72259“ (/2272 )22: / 3 1726 2 A/ 2 2{ L272 / V07 2 <2 I I (4:; 22-; 221’ "A7 , (1.7-2 (c ) (4 pts) Find the unit tangent vector 21—2 and the unit normal vector N as functions of t. 2’) j: , 1/71/02 77222124072“ 2/0727 27/2/22) 22 H ,, , ”22 1“, Jr, 7: / \ l :2, 2 7 (25' j t 1. )I- , C» /2 2/ I 5/ 3 ML 2 j (272/ ,7 7 / / :7,» ~\/ ( ) 2/ ,2, r- '2: /\ J [1/ I \) 7) 2 <2)/ J (22772 f, 12/2I7/ 3 272/227 7 [2 2 ,7 \(22) (1262 {2/} </ ///2( god . _ A, ,, ‘ j " ’ ’ ' 7) 3y , , 7 z ,7 f7, MAJ/2 277/2 2 1' 71/) 2 7222-272 . 7’ 222 22 7» 222/2 (1M2, 722222 2(5’222 (2252/2 " ’7 2/” 2' / 2 ’e I MI W 2 T: 21 L (3) x2 27 (d) (3 pts) Find the curvature of the asteroid’s path as a function of t. )4 M W— , ”if/l &O fl" J’s/i, (e) (4 pts) Find the tangential and normal components of the asteroid’s acceleration/(1T and cm, as functions of 25:7 , (f_( 2. (8 pts, 2 pts each) Match each of the following four functions With the graphs on the following page. . Function: . . Graph: 2/ \/ 1 . (/M/ W: 0/ fl” ,, > f($, y) : g Slfl<$2 —— 1/2) ___C_‘.__..__ (/II ’75 / a (KW/W31 7 fl A W WW» ‘ III/<75! flaw) = m ___.___ 4 f($,y) = '3-Sln(4x +y) I/ ”WI (WW/Ci; (II/‘6? 4 I”, It] {2/ \/// (Wm-,6 cw; 5mg,- MW 3. (10 pts) For each of the following limits, compute it or prove that it does not exist. For full credit you must justify your answers! 1 . ac—l—y a 5 ts 11m 1 293+ 8111 M ( ) < p ) (””11711r2>( 31) (Im— 1| + ly+2l) 15/ 1011111671, 17011‘71111 1 (1/14 1 11 (/7717 161/} (1% 11A 1; 7/1 /V1ol\/f/ 61/6/151111’7/1 My: 1911/11“ 11 1/ 1/ (,1? 12% 14/1 171/1( 11/ 11/2/111/ 17/1 1 I ,, 17/1/7114, (7W11/I/11 1 1‘7 [111 113W 1/ 1 1 1131,1111 [/,/‘/11:2%1711i/})11(1111/1211//Q 1 b 5 It 1- my 42,5121 ()( ps) (931/)1’If100) 1132+y4 1,. 1 ””1111 W1 7’1 ”11 A415; @’//7/“‘7(l,«z)/ 411 m1: 1/ {/1/1/‘1 17/71/11 4. (14 pts) You have designed a rollercoaster track so that at the point (—10, 5, —24), the center of the osculating circle is at (30, —3, 20). (All positions are in meters) Suppose that When the rollercoaster car gets to that point, its acceleration is (16 —5, 5)m 73, and it is slowing down. (a) (3 pts) Find the unit normal vector N to the track at that point. (Hint: Remember. when computing a magnitude factor out anything that you can ) Vain 1775le WI JIM/II I70 (III?! I777 I15” «III/I71 </V (7 (77/37 7777/ 2777 (7777/77) 77 <LW A (/(I/ L/ <M/ 7/ ((> ARK-7777777 II/i717I3/I ((7 J (974/217 I”? 7" L’( 7W7 7/77///71;/// I; .\ /II {M ~’,' I‘ 1 // ,: '1)! (b) (3 pts) Find the normal component Of the car; s acceleration (LN. I / ;_I 1'”. 57/ \ é” fll A} <75, 57/ J > \ .37 19, I52“; / :fI/ / 3) U) 1/ J (M ‘ / (c ) (5 pts) Find the rate at Which the car is slowing down, and the direction 1n Which it is moving (as a unit vector). n77 In I“ [7/ 77 4,! I I II, III II,< I/ I55 'I‘ \ ’7' 7 , “7' " r g! {7’9 / <_ / 1/1 / > /<' 1;} g/ f > / \, N V \[éi’Wf/y (Ii/Iw/I (437 ( pts) HOW fast IS the car geing at that point? 7 (HM/w 7,777 M 6,7177, 7) 7777\4/77Iug (II77 {9:75. ALIII’AII III 7‘ H 7(< {Ii/“Q! 7,7 I 77/17/57 t: éfl m ‘l I, I II III ~ 1 I II I III / I III TII I ...
View Full Document

  • Winter '13
  • Mess
  • 1%, $2, 7 j, 2L

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern