Bio50Exam3Key

Bio50Exam3Key - Name_ BIOL 50 Exam III (100 points total)...

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Name_______________________________ Student I.D.______________________ BIOL 50 Exam III (100 points total) 3/31/04 Page 1 of 7 Signature for honor code This exam is worth 100 points total. The back page has a copy of the genetic code. You may want to separate this page from the others, but do not write any answers on that page – it will NOT be graded . 1. (3 points each) For each of the following terms, write a single sentence definition or description of function: (a) nucleosome Basic unit of chromatin, consisting of DNA wound around an octamer of histone proteins. (b) lagging strand DNA strand being synthesized discontinuously, as a series of Okazaki fragments that will later be ligated into one continuous strand. (c) rRNA Ribosomal RNAs are RNA components of the ribosome, involved in translation. (d) homodimer Protein in which the quaternary structure consists of two identical polypeptide subunits. (e) motif Recognizable amino acid sequence within a polypeptide’s primary structure.
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Name_______________________________ BIOL 50 Exam III (100 points total) 3/31/04 Page 2 of 7 2. (6 points) A single strand of DNA is drawn below. Of the following sequences, only one could be the sequence of this strand. Circle the correct sequence. 5’–TATATA–3’ 5’–ATGCAT–3’ 5’–CGCGCG–3’ 5’–CCCGGG–3’ (The sequence is RYRYRY, where R=purine and Y=pyrimidine) 3. (2 points each) The UAU codon codes for tyrosine. For each of the following, write the sequence of the new codon and specify which amino acid (if any) it codes for. You need list only one correct answer for each, even if several are possible. (a) A missense mutation CAU, GAU, AAU, UUU, UCU, or UGU his asp asn phe ser cys (b) A nonsense mutation UAA or UAG (no amino acid) (c) A frameshift mutation Any insertion of one nucleotide.
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Bio50Exam3Key - Name_ BIOL 50 Exam III (100 points total)...

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