Exam 2 Cheat Sheet.docx - The Plts OT 21 PENN-Plate...

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Unformatted text preview: The Plfitfis OT 21 PENN-Plate caPaClt‘Jf I" Vacuum are 3-00 mm We connect a capacitor C1 = 8.0 ,u.F to a power supply, charge 24.66 .. A parallel'plalc ca- Figure P24.“ apart and 2.00 In in area.A 10.0—kV potential difference is applied to a potential difference V0 = 120 V, and disconnect the DO“ pacitor is made from two across the capacitor. Compute (a) the capacitance; (b) the charge su I Pi 2412 Switch Sis o n (a What is the char 6 lplates 12.0 cm on each side on each plate; and (c) the magnitude of the electric field between ppy( g )' pt: I } g QB. and 4.50 mm apart. Half of C]? (b) What is the energy stored in Cl? (C) Capacil the plates. . . _ . . the space between these plates C2 = 4.0 iiF is initially uncharged. We close swrtch S. Aflcomains only air, butthc other charge no longer flows, what is the potential difference across ea half is filled with Plexiglas® capacitor, and what is the charge on each capacitor? ((1) What ist 0f dielec‘ric ”“5”” 3‘40 (Fig. ”‘4?“ A“ '30,” hungry is _. . - . - connected across the plates. (a) What is the capacrtance of this live long, coaxial cylindrical conductors are separated by vacuu I]... t V * combination? (Hint: Can you think of this capacitor as equivalent V0 = 120V to two capacitors in parallel?) (b) How much energy is stored in the capacitor? (c) if we remove the Plexiglas® but change nothing S C; = 4.0 [.LF else. how much energy will be stored in the capacitor? (Fig. 24.6). The inner cylinder has radius rd and linear charge de sity ‘i'li.. The outer cylinder has inner radius n. and linear chart = “W r = 211,6 = 12V Figure 15.10 SHOWS a SOlll'CC (a battery) Wlll'l em I, = 14 V 3i internal resistance r = 2 n. (For comparison, the internal resi to a 200w lamp. The fm_electmn density in [he wire is ance of a commercial lZ-V lead storage battery is only a few the 8.5 x 1028 per cubic meter. Find (a) the current density and (b) the sandths of an ohm.) The wires to the left of a and to the right of E An Iii-gauge copper wire (the size usually used for lamp cords), with a diameter of 102 mm, carries a constant current of 1.67 A drif‘ 59cm ammeter A are not connected to anything. Determine the respe tive readings V", and I of the idealized voltmeter V and the ide: T ' ' ' " ' Th 18- ' f E 1 25.1 h - ' Hill the equivalent capactance oi the illt-Cflptttlltti new: are;0,gagging?g;,,,::1:§,:mo,‘;;:j;f’::,;§:§;’: ‘ y __ _ in. I“ I‘d} fl Lidpdcllul llClWUlk UDLWCEII pUllllb u ullu U. \U) 1 [ID 14"”.1‘ dllLl U'PJ‘ cnpflcuuia lll hunch 11] (a) £115 lClJliiLELl electric-field magnitude in the Wire; (b) the Potential differer 25.18 to What dlametcr musl a Copper Wn-e have 1f Its TESISIHHCC llny an equrvalent d-uFlcapamtor, (c) The 3-iLF, ll—iLF, and 4:,uF capacitors in parallel in (b) are replaced by an equivalent between two points in the wire 500 m apart; ((3 the resistance C is m be the same as that of an equal length of aluminum wire with BruF capacltor, id) Finally, the lS-yaF and 9-,u.F capac1tors in series in (c) are replaced by an equivalent 6-itF capacitor. 50 0 in length of this wire diameter 2'14 mm? (a) a (to a tc) a M) i we add a 4-H resistor to the battery in Conceptual Example 25.4, "”12433'3if2ilSS-fnsiifin... forming a complete circuit (Fig. 25.17). What are the voltmeter - Var; = Vim We move the voltmeter and ammeter in Example 23.: to article positions in the circuit. What are the readings of the idea] vol meter and ammeterlfli‘e situations shown in (a) Fi .25.]8a iii capacitor. Replace these series capacitors replace these T 9 ”F by an equivalentcapacitur ‘ r 9 HF parallel capacitors by an equivalent capacitor b b b b 24.21 " For the system of capacitors shown in Fig. E2421, a potential difference of 25 V is maintained across ab. (a) What is the equivalent capacitance Of [his syswm between a and b? For the Circuit that we anatyzed in Example 25.5. find the rates is Pm“ me Bqulvalem CSISIafl—Ee or I e nelworx 1" r lg. 10““ in (b) HOW much charge ‘5 stored by ““5 system? (c) How much energy conversion (chemical to electrical) and energy dissipatio I . charge does the 6.5'nF CapaCitor Storc? (d) What is the potential in the battery, the rat: ofenergy dissipation in the 4-0 resistor! an. Mimi I'Ififl fl“ "lll‘fflfil In flunk Mdlt‘i'nr' 11“ dnlll‘fid 1'1;an imi'.‘ 1‘ the battery’s net power output. | 18.0 nF 30.0 nF 10.0 nF| 65nF 25.33 " The circuit shown Figure £25.33 With a "i . . - . . in Fig. E2533 contains two (6’ m (ti the spherical capacrtor described in Example 24d thectton zit batteries, each withanemfflnd 1-6 fl 160" lav ts v lav . 1% v e = m v.r= 0 has charges +Q and -Q on its inner and outer conductors. Fi an internal resistance. and two a b :> :> :> 3 _ . . . , resistors. Find (a) the current in 5,0 Q 9_() (I a 4 a c 2 n g a en 5 a 6 n y, a Hi i; 25 1, the electric potential energy stored iii the capacitor (3) by usrngl the circuit (magnitude and di- 1.4 0 8.0V __ __ __ - , ' , - - reciion)and(b)theterminalvolte 3A 3A 3A t ce C found in Examnle 24.3 and (b) by integrating I age V” mm mm, Mm W ‘37 ‘71:“ fi- " Gaussian surface \w—en v WW Outer shell, charge -Q Use tiauss‘s law to find the capacitance at the spherical capacil ni Finmnle 'M l {Kantian iii ii if the vnluma halurnan the shells in the Circuit shown 1n Fig. 20.11, a IZ-V power supply With u known internal resistance r is connected to a run-down recharg[ __ p, . able batter with unknown emf 8 and internal resistance 1 .0 a- rlgure £0.11 snowsa onuge Circuuot tnelype aescrroeo dill tut: thlolUl tutu capsicum Ul unaitipto Luna. cut: IEL nucucunnm ,. A beam of protons "Nb Figure £27.24 “31""in of ”“5 Shh"? (see Fig; 2615'?)- th he “the“? shown in Fig. 26.22. The capacitor has an initial charge of 5.0 p 11%.?.132,kfifiiett‘ggfizgzifi'gga: cad] l'ESlSlOI‘ and the equlvalem resrstance 0f the newer]: Of fr and it Hitcher-anti i'ur nineinu than uuriir'h at 1' : ll it“ At nihnt ii the field' The beam ems the magnetic Switch field, leaving the field in a direction open perpendicular to its original direction '1' (Fig. E2124). The beam travels a dis- tance of 1.18 cm while in rhefiela'. What I _______ is the magnitude of the magnetic field? in a: You set out to reproduce ‘l‘homson‘s e/m experiment With an ill . _ 0 +Qu ‘Qo is a p accelerating potential of 150 V and a deflecting electric field oi M unifo magnitude 6.0 X 106 N/C. (a) How fast do the electrons move? R b c t = C (b) What magnetic-field magnitude will yield zero beam deflec- = tion? (c) With this magnetic field. how will the electron beam v. 0:. th behave if you increase the accelerating potential above 150 V? scharging Ihe capacitor 7 ".7777" ‘7' [fl ' 7' TM 7"" T rffl’" "W - - . acceleration. (b) Find the radius of the resulting helical path. I __ . . . . . 5 h . . 263.1, l" the cmu‘" shown m Flg' E2631 the batteries have GEE; angular speed of the proton. and the pitch of the helix (the distan negligible internal resrstance and the meters are both idealized. "a I " - - ~ when the switch is Wllh the SWltCh S Open’ the voltmeter reads 15'0 V' (a) Fmd [he closed. the charge A magnetron in a microwave oven emits clecfl'flnfiuc waves emf E of the battery. (b) What Will the ammeter read when the on the capacitor with frequency f = 2450 MHz. What magnetic field strength is ' ' ' scion .- :11“: current required for electrons to move in circular paths with this 0 ECTflflSB 75 o 25 o v 50 o "W” limc‘ frequency? a ‘ __ I E - J n n ‘5‘ M7“ 26.43 -- (P In the circuit shown Figure E26 43 A straight horizontal copper rod carries a current of 5 .0 A fro in Fig. 1326.43 both capacitors are ' west to east in a region between the poles of a large electroma wnat snunt resrsaance is requueo to mate tne Lou-ma, tun-u :flgfihgfs‘igg“: 13:33:": '5 0 :00 net. In this region there is a horizontal magnetic field towardt ‘ _ _ l s 1 1 . . . D . . meter described above into an ammcter with a range of 0 to the potential across each capacitor in: - or 50-0“ northeast (that Is. 45 north of east) With magnitude 1-20 m n . r- be reduced to 10.0 v, and (b) what (in) Find the magnitude and direction of the force on a LOO-m sc Will he the Chm“ 3‘ that time? 30-0 9 tion of rod. (b) While keeping the rod horizontal. how should it ' oriented to maximize the l 34.on N meter deseribed above into a Voltmeter with a range of 0 to l0.0 V? 7 A beam ofprotons (q = to X 10 ” C) moves at 3.0 X lthn through a uniform 2.0-T magnetic field directed along the positi‘ suppose tne meters or example JDJU are connecreo to a air..?'3XiS (Fih- 27.;lli. The velocitv 0f “Ch proton “‘35 i“ the 17-0131 In Fig. 27.30 the magnetic field B is uniformsand perpendicu ent resistor as shown in Fig. 26.161), and the readings obtained [0 the Plane of the figure Pointing 0|“ of the Page The condhfl the meters are the same as in Example 26.10. What is the value carrying cum“ I ‘0 the hilly has three segments: (1) a Shaisht 5' thin mam meictunnn p unrl nil-rail in the mumr diecinutnrl in t mam Wlth length L Perpendicular 10 the ptane 0f the flgure‘ (2 semicircle with radius R, and (3) another straight segment w length L parallel to the x-axis. Find the total magnetic force mgure2 11.102 18 a perspecuve View or a Hat sunace wun a 3.2'0cm in a uniform magnetic field B. The magnetic flux thmt Hun gnu-Fun: m J." m ka pmrI Il-m munmhlrh n? Hm munm 27-35 " A long Wil’fl carry- ‘WEVW "‘7’” ing 4.50 A of current makes ’1 two 90° bonds. as shown in Fig. E2135. The bent part ,3: E of the wire passes through a 30. 60. uniform 0.240—T magnetic I field directed as shown in the 13'". . . . I I I 120' figure and confined to :1 lim- The voltmeter 1n the Cll‘Clltt at Fig. 26.1621 reads 12.0 V and' 7— ited region of space. Find the a' . l u ‘l d d d' I‘ f I. n I I a I ammeter reads 0.100 A. The meta 113515130008 are RV = 0000 31:82:: .22. 11.332233. tango—$3} —— {Fm- H'm vnlfmnfnri and P. = '3 m 0 {FM the ammnfnr‘t What i field exerts on the wire. ...
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