ECE307HW.61.pdf - 2 Design a second-order lowpass filter...

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Unformatted text preview: 2. Design a second-order lowpass filter with Q = 3.5 and 030 = 2712500 = 15707.9633 rad/s using unity gain circuit shown in Figure 2. Find the values of R1, R2, C1, C2 when kIn = 1000. C1 V0 TO Clc; clear; close all; % Active Sallen_Key circuit (2nd order Low Pass Filter % % B % ____________________ % 5A2 + A s + B Choose = l; % O = Equal R, C Method % l = Unity Gain Method B = 7.726252e7; W0 = A = 6727.5058; 1““ = 1000‘ 1.5708e+04 wO : 2*pi*2500%5qrt(B) Q = 3.5%w0fn Q = if choose == 0 %compoment value for normalized LPF 3-5000 Cln : l; C2n : l; R2n : l; RBn : l; RAn = 2—1/9; Ran = 3—1/9; Rbn = (3*Qtl) / (2*(2’1); C1 = K : 3—lfQ %5cale component value 4.45636—07 kf = wO; Cl: Cln/(km‘kf) C2 : C2n/(km*kf) C2 = R2 = R2n*km RB = RENE“ 9.0946e—09 RR = RAn*km Ra = Ran*km Rb : Rbn*km R1 = else %compoment value for normalized LPF 1000 kf : wO; Rln : l; R2n : l; Cln :2*Q; C2n : lf(2*Q); %5cale component value C]. = cm/(kmkf) c2 = C2n/(1cm*kf) R2 = R1 = Rln*km R2 : R2n*]cm 1000 end ...
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