ECE307HW.63.pdf - 4 Design a second-order highpass filter...

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Unformatted text preview: 4. Design a second-order highpass filter with Q = 4.5 and 030 = 2755000 = 31415.9265 rad/s using unity gain circuit shown in Figure 4. Find the values of R1, R2, C1, C2 when km = 10000. R1 clc; clear; close all; 2-: Active SalleniKey 2nd order High Pass Filter % ’a B 5‘2 2., ____________________ % 5"2 + A 5 + B w0 = choose 2 l; i: 0 2 Equal R, C Method ET 1 = Unity Gain Method 3 ' 1416E+O4 B = 7.726252e7; Q = A : 6727.5058; 1cm 2 10000; 4.5000 v10 : 2*pi*5000%5qrt(B) Q = 4.5%wOfA . K = lf choose 2 0 ixcompoment value for normalized HPF Cln = l; C2n = l; Rln = l; R2n = l; 1 RAn : 2—1/9; RBn = l; RCn = 271.’ - Q! R1 = RDn : 1; %scale component value K : 371/0" l.lllle+03 kf : w0; Cl= clnf (1cm*kf) C2 : C2n/(lcm*kf) R2 = R1 : Rlnflcm R2 = R2n*lcm RA : RAnflcm 90000 RB : RBnflcm Rc = RCn*lcm RD : Rmflcm C1 = else Ecompoment value for normalized HPF 3 _ 18316—09 kf 2 WO; Rln = l/(2*Q); R2n = 2*Q; Cln =1; C2n = 1; Escale component value K = 1 R1 = Rinflcm C2 = R2 = R2n*lcm Cl : Cln/(lfln*kf) 3.18316—09 C2 = C2n/(lcm*kf) end ...
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  • Winter '07
  • Z.Aliyazicioglu
  • Kang, High-pass filter, Band-pass filter, Low-pass filter, unity gain, second-order highpass filter

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