ECE307HW.66.pdf - 7 Design a second—order bandstop...

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Unformatted text preview: 7. Design a second—order bandstop filter with Q = 2.5 and 030 = 2712600 = 163362819 rad/s shown in Figure 7. Find the values of RA, RB, R, C when kIn = 1000. 20 Clc; Clear; Close all; 17 Active 2nd order Band stop Filter Er 5"2 + 130 g, 77777777777777777777 it 5"2 + 31 5 + 30 a0 : 56425510; b0 : (2*pi*2600)"2; a1 = 3961.602; wz = sqrt(b0) wO = 2*pi’2600%5qrt(a0) Q : 2.5%w0/a1 ircompoment value far normalized ESP [[1 : 1; 1cm : 1000; A0 = 1; A1 1/Q; B0 = bO/aO; a = llsqrtnao); R : (m+1)/(AO/BO—1); c : (BO/A0—1)/(m+1); Rin = 1; R2n = 1; R3n = m/(i+m); R4n = R; Cln : a; C2n : a/m; C3n : 2’s; C411 : a’C; Escale component Value kf : wO; R1 = Rlnficm R2 : RZnflcm R3 : RSanm c1 = Cln/(km‘kf) cz : C2n/(km*kf) c3 : C3n/(1crn*kf) 173 Cases if w0>wz K : 2+(m/(m+l))‘(AO/BOeleAl/sqrtmm) G : A0/BO*K Mn = K71; RBn RA : RAn*km RB = RBn‘km EEC = RCn’km vaRd : Rdn*km R4 = R4n‘1cm disp('casel‘) N f‘ E :3 || 7‘ 1',‘ E || 1“ elseif w0<wz else end K = 2+(m/ (m+1))*(BOXAO*1*A1*5qrt(BO) hm) G : AOIBO*K RAn = K71; min = 14%ch = 1/671; Rdn = 1; RA : RAn*k-m RB = RBn*]cm %RC : ch*km %Rd = Rdn*k.m c4 : C4nl'(1cm*kf) di5p('case 2') = 2+(m/(m+l))*(BOI’A0717Al*sqrt(B0)fAO) : AOI'BO*K RAn = Kel; RBn = l;%ch = Rel; Rdn = 1; RA 2 RAHHGTL RB = RBn*]Cm %RC : ch*km %Rd = Rdn*k.m di5p('Case L K G so get rid of C4 or R4“ di5p(' 77777777777777777777777 q di5p('Gain Control : ') Egain control ifG>1 RC = (l/G *l)*}cm Rd 2 1cm elseif G<l end RC = (K—1)*lfln Rd = 1cm ...
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  • Fall '07
  • Z.Aliyazicioglu
  • Kang, Trigraph, SEPTA Regional Rail, Band-pass filter, Band-stop filter, RDN, second—order bandstop filter

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