**Unformatted text preview: **In this problem, the function in question satisfies all three of the above requirements, so we can
apply integration by parts. To do so, we first identify the two parts of the function, u and JV.
There are usually more than one way to assign the parts, so it is best to take a few moments
and assign or to be the part that is easy to differentiate, and vto be the part that is easy to integrate.
I (6x + 3) e'z’dx'
u = 6x + 3
dv = e'z‘dt ...

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- Fall '08
- Staff
- Calculus, Integration By Parts