**Unformatted text preview: **The dross-sectional area A of a round pipe of diameter a' is
d 2 2 A=1T At a location along the pipe where the o‘oeeeeotional area is in, the diameter is d1, and the ﬂow speed is w, the
volume flown-lI rate Cl is l
Q=A1v1= Emit”: Take this location to be the wellhead and use the data for that location to calculate the volume flow rate in the
pipe. Before substituting, convert the diameter to the SI unit of meter. Q=%r.r[tl.5t5‘1 m]"'{11.s mrs]=3.ts m’vs The volume flow rate is the same everywhere along the pipe. So at the reﬁnery. where the dross-sectional area
is Hz, the diameter is oz. and the flow speed is b2, the volume ﬂow rate t] can be expressed as l
Q-AJI‘Emfivr. Equate this expression with the one for the wellhead iooetioh, oanoel whatever can be cancelledr and solve for
the pipe diameter d2 at the reﬁneryr in terms of given quantiﬁes. ...

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- Spring '11
- Staff
- Fluid Dynamics, International System of Units, volume flow rate, Sapling, Physics, Fluids