SAPO Fluids 14.1.png - The dross-sectional area A of a...

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Unformatted text preview: The dross-sectional area A of a round pipe of diameter a' is d 2 2 A=1T At a location along the pipe where the o‘oeeeeotional area is in, the diameter is d1, and the flow speed is w, the volume flown-lI rate Cl is l Q=A1v1= Emit”: Take this location to be the wellhead and use the data for that location to calculate the volume flow rate in the pipe. Before substituting, convert the diameter to the SI unit of meter. Q=%r.r[tl.5t5‘1 m]"'{11.s mrs]=3.ts m’vs The volume flow rate is the same everywhere along the pipe. So at the refinery. where the dross-sectional area is Hz, the diameter is oz. and the flow speed is b2, the volume flow rate t] can be expressed as l Q-AJI‘Emfivr. Equate this expression with the one for the wellhead iooetioh, oanoel whatever can be cancelledr and solve for the pipe diameter d2 at the refineryr in terms of given quantifies. ...
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