chapter_04-actualmap - 4 Motion in Two Dimensions CHAPTER...

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4 CHAPTER OUTLINE 4.1 The Position, Velocity, and Acceleration Vectors 4.2 Two-Dimensional Motion with Constant Acceleration 4.3 Projectile Motion 4.4 Uniform Circular Motion 4.5 Tangential and Radial Acceleration 4.6 Relative Velocity and Relative Acceleration Motion in Two Dimensions ANSWERS TO QUESTIONS Q4.1 Yes. An object moving in uniform circular motion moves at a constant speed, but changes its direction of motion. An object cannot accelerate if its velocity is constant. Q4.2 No, you cannot determine the instantaneous velocity. Yes, you can determine the average velocity. The points could be widely separated. In this case, you can only determine the average velocity, which is v x = t . Q4.3 (a) a a a a v v v v (b) a a v v a v a v a v Q4.4 (a) 10 m s ± i (b) 980 . m s 2 ± j Q4.5 The easiest way to approach this problem is to determine acceleration first, velocity second and finally position. Vertical: In free flight, ag y =− . At the top of a projectile’s trajectory, v y = 0. Using this, the maximum height can be found using vv a y y fy iy y f i 22 2 =+ di . Horizontal: a x = 0 , so v x is always the same. To find the horizontal position at maximum height, one needs the flight time, t . Using the vertical information found previously, the flight time can be found using a t fy iy y . The horizontal position is xv t fi x = . If air resistance is taken into account, then the acceleration in both the x and y -directions would have an additional term due to the drag. Q4.6 A parabola. 79
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80 Motion in Two Dimensions Q4.7 The balls will be closest together as the second ball is thrown. Yes, the first ball will always be moving faster, since its flight time is larger, and thus the vertical component of the velocity is larger. The time interval will be one second. No, since the vertical component of the motion determines the flight time. Q4.8 The ball will have the greater speed. Both the rock and the ball will have the same vertical component of the velocity, but the ball will have the additional horizontal component. Q4.9 (a) yes (b) no (c) no (d) yes (e) no Q4.10 Straight up. Throwing the ball any other direction than straight up will give a nonzero speed at the top of the trajectory. Q4.11 No. The projectile with the larger vertical component of the initial velocity will be in the air longer. Q4.12 The projectile is in free fall. Its vertical component of acceleration is the downward acceleration of gravity. Its horizontal component of acceleration is zero. Q4.13 (a) no (b) yes (c) yes (d) no Q4.14 60 ° . The projection angle appears in the expression for horizontal range in the function sin2 θ . This function is the same for 30 ° and 60 ° . Q4.15 The optimal angle would be less than 45 ° . The longer the projectile is in the air, the more that air resistance will change the components of the velocity. Since the vertical component of the motion determines the flight time, an angle less than 45 ° would increase range.
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This note was uploaded on 03/22/2008 for the course PHYS phys230 taught by Professor Hadley during the Spring '08 term at A.T. Still University.

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chapter_04-actualmap - 4 Motion in Two Dimensions CHAPTER...

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