img-215114006.pdf - Ch 5 Solutions to Homework 25 a f(X.15.10.05 0 10 20 30 40 b P(x < 15 = 010(5 = 0.50 c P(12 s x s 18 = 0.10(6 = 0.60 d E(x)=10 20=15

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  • Spring '16
  • Skordi
  • Harshad number, 20 30 40, process standard deviation

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