{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

EE 302 - HW 3 - 40 Ω 40 Ω 12 V 20 Ω 12 Ω 10 Ω 8Ω...

Info icon This preview shows pages 1–6. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 2, Problem 26. For the circuit in Fig. 2.90, i o =2 A. Calculate i x and the total power dissipated by the circuit. 2 4 8 i o 16 i x The voltage across the 8Ω resistor is ½ that across the 16Ω. A. True B. False
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Chapter 2, Problem 32. Find i 1 through i 4 in the circuit in Fig. 2.96. The 4 resistors are all in parallel with each other. A. True B. False The following lists the currents in order of lowest to highest. A. i1, i2, i3, i4 B. I2, i3, i4, i1 C. I3, i4, i1, i2 D. None of the above
Image of page 2
Chapter 2, Problem 34. Using series/parallel resistance combination, find the equivalent resistance seen by the source in the circuit of Fig. 2.98. Find the overall dissipated power. 20 + _ 40
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 6
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 40 Ω 40 Ω 12 V 20 Ω 12 Ω 10 Ω 8Ω 10Ω Chapter 2, Problem 38. Find R eq and i o in the circuit of Fig. 2.102. 5 Ω 6 Ω + _ 15 Ω 20 Ω 40 V 60 Ω 12 Ω 80 Ω R eq i o The 60Ω resistor is not in parallel with the 12Ω and 6Ω resistors because they do not share a common pair of nodes. A. True B. False Chapter 2, Problem 41. If R eq = 50 Ω in the circuit in Fig. 2.105, find R . In order for Req to equal 50 Ω, the net resistance in series with the 30 Ω resistor must equal A. 20 Ω B. 50 Ω C. 30 Ω D. Cannot say Chapter 2, Problem 45. Find the equivalent resistance at terminals a-b of each circuit in Fig. 2.109....
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern