ch03 SOLUTION.pdf

# ch03 SOLUTION.pdf - Chapter 3 Descriptive Statistics 1...

• 8

This preview shows page 1 - 3 out of 8 pages.

Chapter 3: Descriptive Statistics 1 Chapter 3 Descriptive Statistics SOLUTIONS TO PROBLEMS IN CHAPTER 3 ANS of Que No. 1,2,3,4,5,6,7,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,27,28,29,30,31,32,33 3.1 Mode 2, 2, 3, 3, 4, 4, 4, 4, 5, 6, 7, 8, 8, 8, 9 The mode = 4 4 is the most frequently occurring value 3.2 Median for values in 3.1 Arrange in ascending order: 2, 2, 3, 3, 4, 4, 4, 4, 5, 6, 7, 8, 8, 8, 9 There are 15 terms. Since there are an odd number of terms, the median is the middle number. The median = 4 Using the formula, the median is located at the n + 1 th term = 15+1 = 16 = 8 th term 2 2 2 The 8 th term = 4 3.3 Median Arrange terms in ascending order: 073, 167, 199, 213, 243, 345, 444, 524, 609, 682 There are 10 terms. Since there are an even number of terms, the median is the average of the two middle terms: Median = 243 + 345 = 588 = 294 Using the formula, 2 2 the median is located at the n + 1 th term. n = 10 therefore 10 + 1 = 11 = 5.5 th term. 2 2 2 The median is located halfway between the 5 th and 6 th terms. 5 th term = 243 6 th term = 345 Halfway between 243 and 345 is the median = 294 3.4 Mean 17.3 44.5 µ = Σ x/N = 333.6/8 = 41.7 31.6 40.0 52.8 x = Σ x/n = 333.6/8 = 41.7 38.8 30.1 78.5 (It is not stated in the problem whether the Σ x = 333.6 data represent as population or a sample). 3.5 Mean 7 + (-2) + 5 + 9 + 0 + (-3) + (-6) + (-7) + (-4) + (-5) + 2 + (-8) = Σ x = (-12) (It is not stated in the problem whether the data represent a population or a sample). µ = Σ x/N = -12/12 = -1 x = Σ x/n = -12/12 = -1 3.6 Rearranging the data into ascending order: 11, 13, 16, 17, 18, 19, 20, 25, 27, 28, 29, 30, 32, 33, 34 25 . 5 ) 15 ( 100 35 = = i P 35 is located at the 5 + 1 = 6 th term P 35 = 19 25 . 8 ) 15 ( 100 55 = = i P 55 is located at the 8 + 1 = 9 th term P 55 = 27 Q 1 = P 25 75 . 3 ) 15 ( 100 25 = = i Q 1 = P 25 is located at the 3 + 1 = 4 th term Q 1 = 17 Q 2 = Median The median is located at the term th th 8 2 1 15 = + Q 2 = 25 Q 3 = P 75 25 . 11 ) 15 ( 100 75 = = i Q 3 = P 75 is located at the 11 + 1 = 12 th term Q 3 = 30

Subscribe to view the full document.

Chapter 3: Descriptive Statistics 2 3.7 Rearranging the data in ascending order: 80, 94, 97, 105, 107, 112, 116, 116, 118, 119, 120, 127, 128, 138, 138, 139, 142, 143, 144, 145, 150, 162, 171, 172 n = 24 8 . 4 ) 24 ( 100 20 = = i P 20 is located at the 4 + 1 = 5 th term P 20 = 107 28 . 11 ) 24 ( 100 47 = = i P 47 is located at the 11 + 1 = 12 th term P 47 = 127 92 . 19 ) 24 ( 100 83 = = i P 83 is located at the 19 + 1 = 20 th term P 83 = 145 Q 1 = P 25 6 ) 24 ( 100 25 = = i Q 1 is located at the 6.5 th term Q 1 = (112 + 116)/ 2 = 114 Q 2 = Median The median is located at the: term th th 5 . 12 2 1 24 = + Q 2 = (127 + 128)/ 2 = 127.5 Q 3 = P 75 18 ) 24 ( 100 75 = = i Q 3 is located at the 18.5 th term Q 3 = (143 + 144)/ 2 = 143.5 3.10 n = 17 Mean = 59 . 3 17 61 = = N x The median is located at the th + 2 1 17 = 9 th
You've reached the end of this preview.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern