This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: schneiter (tcs639) HW21 Ross (89152) 1 This printout should have 13 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 3) 10.0 points A simple harmonic oscillator takes 6 . 1 s to undergo five complete vibrations. Find the period of its motion. Correct answer: 1 . 22 s. Explanation: Let : t = 6 . 1 s and n = 5 . The period is, by definition, how long it takes the oscillator to complete one full cycle; i.e. , to return to where it started. Since we are told how long it takes to undergo five complete vibrations, the period is T = t n = 6 . 1 s 5 = 1 . 22 s . 002 (part 2 of 3) 10.0 points Calculate the frequency. Correct answer: 0 . 819672 Hz. Explanation: The frequency is how many vibrations the oscillator undergoes per unit time, or the re ciprocal of the period: f = 1 T = 1 1 . 22 s = . 819672 Hz 003 (part 3 of 3) 10.0 points Find the angular frequency. Correct answer: 5 . 15015 rad / s. Explanation: = 2 f = 2 (0 . 819672 Hz) = 5 . 15015 rad / s . 004 10.0 points A 0 . 312 kg mass is attached to a spring and undergoes simple harmonic motion with a pe riod of 0 . 74 s. The total energy of the system is 5 J. Find the amplitude of the motion. Correct answer: 0 . 666768 m....
View
Full
Document
This note was uploaded on 04/23/2009 for the course PHYS 152 taught by Professor Button during the Spring '08 term at IUPUI.
 Spring '08
 BUTTON
 mechanics

Click to edit the document details