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Unformatted text preview: schneiter (tcs639) – HW21 – Ross – (89152) 1 This printout should have 13 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 3) 10.0 points A simple harmonic oscillator takes 6 . 1 s to undergo five complete vibrations. Find the period of its motion. Correct answer: 1 . 22 s. Explanation: Let : t = 6 . 1 s and n = 5 . The period is, by definition, how long it takes the oscillator to complete one full cycle; i.e. , to return to where it started. Since we are told how long it takes to undergo five complete vibrations, the period is T = t n = 6 . 1 s 5 = 1 . 22 s . 002 (part 2 of 3) 10.0 points Calculate the frequency. Correct answer: 0 . 819672 Hz. Explanation: The frequency is how many vibrations the oscillator undergoes per unit time, or the re ciprocal of the period: f = 1 T = 1 1 . 22 s = . 819672 Hz 003 (part 3 of 3) 10.0 points Find the angular frequency. Correct answer: 5 . 15015 rad / s. Explanation: ω = 2 π f = 2 π (0 . 819672 Hz) = 5 . 15015 rad / s . 004 10.0 points A 0 . 312 kg mass is attached to a spring and undergoes simple harmonic motion with a pe riod of 0 . 74 s. The total energy of the system is 5 J. Find the amplitude of the motion. Correct answer: 0 . 666768 m....
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 Spring '08
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 mechanics, Simple Harmonic Motion, 1 K, 1 k, 2 m, 2 g

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