This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: schneiter (tcs639) – HW18 – Ross – (89152) 1 This printout should have 7 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points The system shown in the figure is in equilib rium. A 13 kg mass is on the table. A string attached to the knot and the ceiling makes an angle of 48 ◦ with the horizontal. The coeffi cient of the static friction between the 13 kg mass and the surface on which it rests is 0 . 44. The acceleration of gravity is 9 . 8 m / s 2 . 13 kg m 4 8 ◦ What is the largest mass m can have and still preserve the equilibrium? Correct answer: 6 . 35271 kg. Explanation: Let : M = 13 kg , m = 6 . 35271 kg , and θ = 48 ◦ . Basic Concepts: The net force exerted on an object in equilibrium equals zero. Solution: For the system to remain in equi librium, the net forces on both M and m should be zero; and thus the tension in the rope has an upper bound value T max T max cos θ = μM g , so (1) T max = μM g cos θ = (0 . 44) (13 kg) (9 . 8 m / s 2 ) cos(48 ◦ ) = 83 . 7744 N . For m to remain in equilibrium T max sin θ = m max g , so (2) m max = T max sin θ g = (83 . 7744 N) sin(48 ◦ ) (9 . 8 m / s 2 ) = 6 . 35271 kg ....
View
Full
Document
This note was uploaded on 04/23/2009 for the course PHYS 152 taught by Professor Button during the Spring '08 term at IUPUI.
 Spring '08
 BUTTON
 mechanics

Click to edit the document details