HW9 - schneiter (tcs639) HW09 Ross (89152) 1 This print-out...

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Unformatted text preview: schneiter (tcs639) HW09 Ross (89152) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points A force vector F = F x + F y acts on a particle that undergoes a displacement of vectors = s x + s y . Let: F x = 7 N, F y =- 5 N, s x = 3 m, and s y = 2 m. Find the work done by the force on the particle. Correct answer: 11 J. Explanation: The work is given by W = vector F vectors = F x s x + F y s y = (7 N) (3 m) + (- 5 N) (2 m) = 11 J . 002 (part 2 of 2) 10.0 points Find the angle between vector F and vectors . Correct answer: 69 . 2278 . Explanation: Since W = vector F vectors = vextendsingle vextendsingle vextendsingle vector F vextendsingle vextendsingle vextendsingle | vectors | cos . The first and the third sides can be solved for to give = cos 1 W vextendsingle vextendsingle vextendsingle vector F vextendsingle vextendsingle vextendsingle | vectors | . First of all vextendsingle vextendsingle vextendsingle vector F vextendsingle vextendsingle vextendsingle = radicalBig F 2 x + F 2 y = radicalBig (7 N) 2 + (- 5 N) 2 = 8 . 60233 N and | vectors | = radicalBig s 2 x + s 2 y = radicalbig 3 m...
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This note was uploaded on 04/23/2009 for the course PHYS 152 taught by Professor Button during the Spring '08 term at IUPUI.

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HW9 - schneiter (tcs639) HW09 Ross (89152) 1 This print-out...

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