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**Unformatted text preview: **schneiter (tcs639) – HW07 – Ross – (89152) 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points Consider the 693 N weight held by two cables shown below. The left-hand cable had tension T 2 and makes an angle of θ 2 with the ceiling. The right-hand cable had tension 540 N and makes an angle of 42 ◦ with the ceiling. The right-hand cable makes an angle of 42 ◦ with the ceiling and has a tension of 540 N . 693 N T 2 5 4 N 4 2 ◦ θ 2 a) What is the tension T 2 in the left-hand cable slanted at an angle of θ 2 with respect to the wall? Correct answer: 520 . 62 N. Explanation: Observe the free-body diagram below. F 2 F 1 θ 1 θ 2 W g Note: The sum of the x- and y-components of F 1 , F 2 , and W g are equal to zero. Given : W g = 693 N , F 1 = 540 N , θ 1 = 42 ◦ , and θ 2 = 90 ◦- θ . Basic Concept: Vertically and Horizontally, we have F x net = F x 1- F x 2 = 0 = F 1 cos θ 1- F 2 cos θ 2 = 0 (1) F y net = F y 1 + F y 2- W g = 0 = F 1 sin θ 1 + F 2 sin θ 2- W g = 0 (2) Solution: Using Eqs. 1 and 2, we have F x 2 = F 1 cos θ 1 (1) = (540 N) cos42 ◦ = 401 . 298 N , and F y 2 = F 3- F 1 sin θ 1 (2) = 693 N- (540 N) sin42 ◦ = 693 N- 361 . 331 N = 331 . 669 N , so F 2 = radicalBig ( F x 2 ) 2 + ( F y 2 ) 2 = radicalBig (401 . 298 N) 2 + (331 . 669 N) 2 = 520 . 62 N ....

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