This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: schneiter (tcs639) HW07 Ross (89152) 1 This printout should have 9 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points Consider the 693 N weight held by two cables shown below. The lefthand cable had tension T 2 and makes an angle of 2 with the ceiling. The righthand cable had tension 540 N and makes an angle of 42 with the ceiling. The righthand cable makes an angle of 42 with the ceiling and has a tension of 540 N . 693 N T 2 5 4 N 4 2 2 a) What is the tension T 2 in the lefthand cable slanted at an angle of 2 with respect to the wall? Correct answer: 520 . 62 N. Explanation: Observe the freebody diagram below. F 2 F 1 1 2 W g Note: The sum of the x and ycomponents of F 1 , F 2 , and W g are equal to zero. Given : W g = 693 N , F 1 = 540 N , 1 = 42 , and 2 = 90  . Basic Concept: Vertically and Horizontally, we have F x net = F x 1 F x 2 = 0 = F 1 cos 1 F 2 cos 2 = 0 (1) F y net = F y 1 + F y 2 W g = 0 = F 1 sin 1 + F 2 sin 2 W g = 0 (2) Solution: Using Eqs. 1 and 2, we have F x 2 = F 1 cos 1 (1) = (540 N) cos42 = 401 . 298 N , and F y 2 = F 3 F 1 sin 1 (2) = 693 N (540 N) sin42 = 693 N 361 . 331 N = 331 . 669 N , so F 2 = radicalBig ( F x 2 ) 2 + ( F y 2 ) 2 = radicalBig (401 . 298 N) 2 + (331 . 669 N) 2 = 520 . 62 N ....
View Full Document
 Spring '08
 BUTTON
 mechanics

Click to edit the document details