HW6 - schneiter (tcs639) HW06 Ross (89152) 1 This print-out...

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Unformatted text preview: schneiter (tcs639) HW06 Ross (89152) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 3) 10.0 points A boat moves through the water with two forces acting on it. One is a 2478 N forward push by the motor on the propeller, and the other is an 2238 N resistive force due to the water around the bow. What is the acceleration of the 1185 kg boat? Correct answer: 0 . 202532 m / s 2 . Explanation: Given : F 1 = 2478 N , F 2 = 2238 N , and m = 1185 kg . 2478 N 2238 N The forces are unbalanced, so the net force is F net = m a = F 1 F 2 and a = F 1 F 2 m = 2478 N 2238 N 1185 kg = . 202532 m / s 2 forward. 002 (part 2 of 3) 10.0 points If it starts from rest, how far will it move in 12 . 1 s? Correct answer: 14 . 8263 m. Explanation: Given : t = 12 . 1 s Under acceleration, x = v i t + 1 2 a ( t ) 2 = 1 2 a ( t ) 2 since v i = 0 m/s. Thus x = 1 2 a ( t ) 2 = 1 2 ( . 202532 m / s 2 ) (12 . 1 s) 2 = 14 . 8263 m . 003 (part 3 of 3) 10.0 points What will its velocity be at the end of this time interval?...
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This note was uploaded on 04/23/2009 for the course PHYS 152 taught by Professor Button during the Spring '08 term at IUPUI.

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HW6 - schneiter (tcs639) HW06 Ross (89152) 1 This print-out...

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