HW4 - schneiter (tcs639) HW04 Ross (89152) 1 This print-out...

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Unformatted text preview: schneiter (tcs639) HW04 Ross (89152) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 3) 10.0 points Two canoeists in identical canoes exert the same effort paddling and hence maintain the same speed relative to the water. One pad- dles directly upstream (and moves upstream), whereas the other paddles directly down- stream. With downstream as the positive direction, an observer on shore determines the velocities of the two canoes to be- 1 . 5 m / s and 2 . 7 m / s, respectively. What is the speed of the water relative to shore? Correct answer: 0 . 6 m / s. Explanation: Let v 1 s = velocity of canoe1 relative to shore, v 2 s = velocity of canoe2 relative to shore, v 1 w = velocity of canoe1 relative to water, v 2 w = velocity of canoe2 relative to water, and v ws = velocity of water relative to shore. Given : v 1 s =- 1 . 5 m / s , v 2 s = 2 . 7 m / s , and v 1 w = v 2 w . v cs = v cw + v ws For the first canoe (moving upstream) v 1 s = v ws- v 1 w For the second canoe (moving downstream) v 2 s = v ws + v 2 w adding these equations v 1 s + v 2 s = 2 v ws since v 1 w = v 2 w . Thus v ws = v 1 s + v 2 s 2 =- 1 . 5 m / s + 2 . 7 m / s 2 = . 6 m / s . 002 (part 2 of 3) 10.0 points What is the speed of the first canoe relative to the water?...
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This note was uploaded on 04/23/2009 for the course PHYS 152 taught by Professor Button during the Spring '08 term at IUPUI.

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HW4 - schneiter (tcs639) HW04 Ross (89152) 1 This print-out...

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