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Unformatted text preview: schneiter (tcs639) HW02 Ross (89152) 1 This printout should have 8 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 3) 10.0 points The position of a softball tossed vertically upward is described by the equation y = c 1 t c 2 t 2 , where y is in meters, t in seconds, c 1 = 8 . 62 m / s, and c 2 = 2 . 77 m / s 2 . Find the balls initial speed v at t = 0 s. Correct answer: 8 . 62 m / s. Explanation: Basic Concepts: v = dx dt a = dv dt = d 2 x dt 2 Solution: The velocity is simply the derivative of y with respect to t : v = dy dt = 8 . 62 m / s 2(2 . 77 m / s 2 ) t, which at t = 0 is v = 8 . 62 m / s . 002 (part 2 of 3) 10.0 points Find its velocity at t = 0 . 691 s. Correct answer: 4 . 79186 m / s. Explanation: Substituting t = 0 . 691 s into the above formula for v , we obtain v = 8 . 62 m / s 2(2 . 77 m / s 2 )(0 . 691 s) = 4 . 79186 m / s ....
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This note was uploaded on 04/23/2009 for the course PHYS 152 taught by Professor Button during the Spring '08 term at IUPUI.
 Spring '08
 BUTTON
 mechanics

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