HW1 - schneiter (tcs639) HW01 Ross (89152) 1 This print-out...

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Unformatted text preview: schneiter (tcs639) HW01 Ross (89152) 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points When the Sun is directly overhead, a hawk dives toward the ground at a speed of 3 . 62 m / s. If the direction of his motion is at an an- gle of 24 . 5 below the horizontal, calculate the speed of his shadow moving along the ground. Correct answer: 3 . 29406 m / s. Explanation: The velocity of the shadow of the hawk on the ground will be equal to the horizontal projection of the velocity of the hawk (draw a picture). We know that the angle between the velocity of the hawk and the horizontal is = 24 . 5 , therefore the velocity u of the shadow on the ground will be u = v cos = (3 . 62 m / s) cos (24 . 5 ) = 3 . 29406 m / s . 002 10.0 points A quarterback takes the ball from the line of scrimmage, runs backward for 20 yards, then runs sideways parallel to the line of scrim-...
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HW1 - schneiter (tcs639) HW01 Ross (89152) 1 This print-out...

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