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# solution_pdf3 - McPartlin(anm464 – assignment 8 –...

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Unformatted text preview: McPartlin (anm464) – assignment 8 – frommhold – (58025) 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 16.66 points Consider the setup of a single slit experiment shown in the figure. The first minimum for 400 nm light is at y 1 . The first minimum for 479 nm light is at y 2 . y L a S 1 S 2 θ viewing screen What is the ratio y 2 y 1 ? Correct answer: 1 . 1975. Explanation: The first minimum is at y = λL a For the first light, y 1 = λ 1 L a For the second light, y 2 = λ 2 L a Therefore y 2 y 1 = λ 2 λ 1 = (479 nm) (400 nm) = 1 . 1975 . 002 16.66 points A screen is illuminated by light with wave length λ as shown in the figure below. The distance from the slits to the screen is L . y L d S 1 S 2 θ viewing screen Using the small angle approximation ( θ = sin θ = tan θ ) , how far apart y is the fourth bright fringe from the central bright fringe? 1. y = 5 L d λ 2. None of these. 3. y = 7 2 L λ d 4. y = 4 L λ d correct 5. y = 4 L d λ 6. y = 5 L λ d 7. y = 7 2 d λ L 8. y = 7 2 L d λ 9. y = 5 d λ L 10. y = 4 d λ L Explanation: Basic Concepts: For bright fringes, we have d sin θ = m λ , and for dark fringes, we have d sin θ = parenleftbigg m + 1 2 parenrightbigg λ ,...
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## This note was uploaded on 04/26/2009 for the course PHY 44135 taught by Professor Frommhold during the Spring '09 term at University of Texas.

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solution_pdf3 - McPartlin(anm464 – assignment 8 –...

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