homework_21.1_sol

homework_21.1_sol - Homework#3 Solution 12.5 q I JV J D2 Ix...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Homework #3 Solution 12.5 q I JV J D2 Ix J J J J AJ 2 At A x 4 JJ V 3 4Ix 42 10 A2 10000m J D2 2 J 2 1.09762 102 3 m 2 2 C2 2 JJJ V 2 2 2 2 5.82 107 2 2 2J 2s 2m 22 200V 2 2 2 2 J electron J 2 J D J 3.31cm The required wire diameter is about 3.31 cm. 12.6 J diffusion J M JC J J At x 2 J J M JD 2 C J J J t 4x 1.772 102 9 m2 kg 2 2 2 1m 2 2 2 0.00042 2 02 3 s m 2 5.842 102 11 kg 42 0.01m s The rate at which carbon dioxide diffuse to the algae is kg 5.842 102 11 s 2 12.7 (a) Series: R S = R1 + R 2 = 5 + 10 = 15 (b) Parellel: 1 1 10 RP = = = 3.33 1 1 1 1 3 + + R1 R 2 5 10 12.8 R equiv = 12.13 1 1 1 + R1 R 2 + R3 = 1 1 1 + 20 10 + 5 = 20 35 + 5 = 11.67 3 3 . Let assume the heat resistance of each panel is the same, and denoted as R. Case I: uniformly covered with three layers R panel = 3R, J heat = 1000TApanel T T = , Qheat ,total ,1 = 1000 Apanel J heat = R panel 3R 3R Case II: half covered with four layers and half two layers R panel ,a = 2 R, J heat , a = R panel ,b = 4 R, J heat ,b = T R panel ,a T R panel ,b = = 250TApanel T , Qheat ,total , a = 500 Apanel J heat , a = 2R R 125TApanel T , Qheat ,total ,b = 500 Apanel J heat ,b = 4R R 375TApanel R Because 1000/3 < 375, so the first case, i.e., uniformly covering, will result in less energy consumption. Qheat ,total ,2 = Qheat ,total ,a + Qheat ,total ,b = ...
View Full Document

Page1 / 2

homework_21.1_sol - Homework#3 Solution 12.5 q I JV J D2 Ix...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online